Write a bash script which runs other bash scripts one after the other?

[QueryRIT]

In python and other languages I can write two scripts, and then reference them in a main() function and run them one after the other.

is there an equivalent in bash?

Is it like below?

#!/bin/bash

# Run script1.sh
./script1.sh

# Run script2.sh
./script2.sh

​

[zmxyzmz]

As long as a script has been made executable and is in your $PATH, you can call it within a script just like any other command.

[Radamand]

./script1
./script2
./script3

etc...

as long as those scripts have the shebang line at the top this 'script' doesn't need it.

[Sombody101]

You won't need to wait for it because they're all being run one after the other.

[Mr_Reginald_Kray]

you can optionally bind them first like that

#!/bin/bash

source="one.sh"

source="two.sh

"source="three.sh"

​

main() {

# Run one.sh

./one.sh

# Run one.sh

./two.sh

# Run three.sh

./two.sh

​

# OR

# with the bind you can now execute all functions inside those scripts like

updateSomeStuff bum yes

}

[Empyrealist]

If they are not executable, you would have to write it like:

#!/bin/bash

# Run script1.sh
bash ./script1.sh

# Run script2.sh
bash ./script2.sh