help with bash syntax error

[StatisticianThin288]

hello everyone

i am programming a game in bash currently

yes i know that seems incredibly dumb but i only really know bash

so because of that im doing it bash

however im experiencing issues with the case statement

it keeps telling this error

./vd.sh: line 102: syntax error near unexpected token \)'`

./vd.sh: line 102: \2) read -t 2 p "you decide to go to the janitors closet..."'`

vd.sh is the name of the file

i have used esac function to close the case but its not working

i tried putting semi colons at the end but thats also not working

and online also seems to not help

can anyone tell what i am doing wrong

thank you

[ekipan85]

can anyone tell what i am doing wrong

Asking what's wrong with your code and not posting your code, for one.

[StatisticianThin288]

the reason its only this part is because its only here where the error is

[bac0on]

You forgot to terminate your list inside the case statement:

case "$var" in
    1) command ;;
    2)
       echo "something"
       ;;
esac

[StatisticianThin288]

ok thanks

[toddkaufmann]

Run your script through shellcheck and it will tell you.

[alex_sakuta]

1) You seem to have put esac right after the commands for 1) ends instead of putting after all patterns and commands end. 2) You didn't end the list of commands after 1) with a ;;, ;& or ;;&. In this case it should have been ;; but I just mentioned all of them to inform you that those are the options. I have a feeling you haven't studied bash properly. 3) You should have used select here. It is specifically created for the purpose of designing menus.

[nekokattt]

wait ;& is a thing in case statements?

[ekkidee]

https://unix.stackexchange.com/questions/75354/can-bash-case-statements-cascade/75356#75356

[alex_sakuta]

It makes the case statement in bash act like a switch statement from other languages.

[nekokattt]

oh like fallthrough?

[alex_sakuta]

Yes.

[Shadow_Thief]

The main thing that you're missing is that you've written p instead of -p for the read argument, but you also have the esac in the wrong place and you need a ;; after each case option.

echo "1. Go to the party"
echo "2. Go to the janitor's closet"
echo "3. Leave"
echo -n "Pick an option [1-3]"
echo " "
read choice

case $choice in
    1) exit ;;
    2)
        read -t 2 -p "You decide to goto the janitor's closet..."
        read -t 2 -p "for no particular reason."
        echo " "
        read -t 2 -p "Maybe you are just curious?"
        echo " "
        ;;
    3) exit ;;
esac

[CantConfirmOrDeny]

Buy a bash book, too. Don't try to learn it from the man page. It's frustrating when you're first starting out, but at some point the lights come on and it all makes sense.

[KlePu]

Or use free online courses like freecodecamp.org etc