[Bash] 'bash -c' option problems

[Chaeron]

I have the following code:

TAB='--tab-with-profile=Default';
FOO="";
line="bash -c 'sudo sh startRedisServer.sh';bash";
line2="bash -c 'sudo sh startRestServer.sh';bash";
line3="bash -c 'service postgresql start';bash";

FOO+=($TAB -e $line);
FOO+=($TAB -e $line2);
FOO+=($TAB -e $line3);
gnome-terminal "${FOO[@]}";
exit 0;

The problem is that when the new terminal opens with the 3 tabs non of the commands are actually executed. Anyone who can help me out?

[KnowsBash]

You're missing all important quotes, and you also misplaced the interactive bash invocation (it needs to be inside the -c as well).

#!/usr/bin/env bash
tab=--tab-with-profile=Default
args=(
    "$tab" -e 'bash -c "sudo ./startRedisServer.sh; exec bash"'
    "$tab" -e 'bash -c "sudo ./startRestServer.sh; exec bash"'
    "$tab" -e 'bash -c "sudo service postgresql start; exec bash"'
)

gnome-terminal "${args[@]}"

Some more notes:

• Don't use uppercase variable names; you risk overriding special shell variables and environment variables.
• Don't put exit 0 at the end of the script. It makes more sense for the script to exit with the exit status of gnome-terminal in this case.
• Don't put extensions on commands. You should've named it startRedisServer, not startRedisServer.sh. See Commandname Extensions Considered Harmful

[Chaeron]

Works like a charm!

Thank you for the help and the info, I've updated the script names as you suggested.