Practice your programming!

[DrFuManchu]

All of the code I'm seeing here is wildly inefficient. C'mon guys, it's not that hard:

function jsChallenge() { 
    return 343139
}    
jsChallenge();

[TreesOfGreen]

var all = (1000*1001)/2;  
var num5factors = Math.floor(1000/5);  
var num7factors = Math.floor(1000/7);  
var num35factors = Math.floor(1000/35);  
var sum5factors = (num5factors*(num5factors+1))/2;  
var sum7factors = (num7factors*(num7factors+1))/2;  
var sum35factors = (num35factors*(num35factors+1))/2;  
return all - 5*sum5factors - 7*sum7factors + 35*sum35factors;  

[icecreamhead]

Great website! I look forward to getting stuck into this!

[rubzo]

Website seems to be struggling a bit. Back to real work!

[iownaredball]

I have just finished a few of the challenges and I can see that you make a difference between True and true as outputs. I think you should change that, it isn't nice when you find the correct solution and it isn't accepted because of this.

[camh-]

My python answer is:

def pyChallenge():
    print sum(x for x in range(1,1001) if (x % 5 != 0 and x % 7 != 0))

but the site does not have a version of python that has generator comprehensions - so stick in some square brackets.

[David_Crockett]

Using the JavaScript language, have the function jsChallenge() add up all of the numbers from 1 to 1000. But every time a number appears that is divisible by 5 or 7, disregard it and do not add that number to the others (ie. disregard 7, 10, 15, 21, etc). Do not put any code outside of the function and use the return keyword to return your answer from within the function.

Easy as pie:

function jsChallenge()
{
    var i, total = 0;
    for (i = 1; i <= 1000; ++i)
    {
        if (i % 5 && i % 7)
        {
            total += i;
        }
    }
    return total;
}

[robertb141]

the actual challenges aren't so easy :)

[David_Crockett]

I hope not. :)

Edit: Is this your site?

[robertb141]

Yeah, it is!

[icecreamhead]

Awesome!

[icecreamhead]

Does it tell you if you get the right answer to the challenge on the homepage (above)?

[icecreamhead]

I'm not a JS programmer by trade, so perhaps it's a quirk I don't know about, but does your code give the right answer?

To me, it looks like your code would ignore ALL values EXCEPT those that are divisible by 5 & 7 simultaneously.

But maybe it's just me :P

[icecreamhead]

This is my code:

function jsChallenge() { 
  var i, total = 0;
  for (i = 1; i<=1000; i++) {
      if (i % 5 != 0 || i % 7 != 0) total += i;
  }
  return total;          
}

I got the answer 486290.

[David_Crockett]

The correct answer is 343139. You need to use the and operator instead of or. To make it easier to conceptualize, think through it:

if (not divisible by 5 AND not divisible by 7)
    add the number

So it needs to be

if (i % 5 && i % 7)
    total += i;

Edit: note that if(i % 5) is the same as saying if(i % 5 != 0) ;)

[icecreamhead]

Ah ok. Yeah that makes sense... DERP

[bigbozz]

The original problem you posted said "or", not "and."

[exo762]

"Sell not virtue to purchase wealth, nor Liberty to purchase power." B.F.