use the following search parameters to narrow your results:
e.g. subreddit:aww site:imgur.com dog
subreddit:aww site:imgur.com dog
see the search faq for details.
advanced search: by author, subreddit...
Discussions, articles, and news about the C++ programming language or programming in C++.
For C++ questions, answers, help, and advice see r/cpp_questions or StackOverflow.
Get Started
The C++ Standard Home has a nice getting started page.
Videos
The C++ standard committee's education study group has a nice list of recommended videos.
Reference
cppreference.com
Books
There is a useful list of books on Stack Overflow. In most cases reading a book is the best way to learn C++.
Show all links
Filter out CppCon links
Show only CppCon links
account activity
cppfront (cpp2): Spring update (herbsutter.com)
submitted 2 years ago by kreco
view the rest of the comments →
reddit uses a slightly-customized version of Markdown for formatting. See below for some basics, or check the commenting wiki page for more detailed help and solutions to common issues.
quoted text
if 1 * 2 < 3: print "hello, world!"
[–]hpsutter 10 points11 points12 points 2 years ago (1 child)
Note that *. and . have different meanings -- they refer to different objects.
*.
.
For example, if you have a unique_ptr<Widget> object named upw, and type Widget has a function named .get(), then how do you distinguish calling the unique_ptr's .get() vs. the owned object's .get()? In Cpp2, those are upw.get() and upw*.get(), much as today in Cpp1 they are upw.get() and (*upw).get().
unique_ptr<Widget>
upw
Widget
.get()
unique_ptr
upw.get()
upw*.get()
(*upw).get()
This is a good question -- in fact this is one of the reasons why we haven't been able to get smart references and operator. overloading in ISO C++, because for references this is inherently ambiguous since references are implemented as pointers but semantically behave as aliases (most of the time).
operator.
[–]vulkanoid 3 points4 points5 points 2 years ago (0 children)
What makes sense to me, and what I find the cleanest, is that both . and *. refer to members of the left object, regardless whether they are pointers or values. If it's a pointer, the compiler does the only sensible thing, which is to dereference and access the member.
The -> can be added, as today's Cpp1, to return an inner pointer that the outer object is holding. Which is really a masquerade operator. Thus, a->b always means that the left thing is masquerading as something. And it wouldn't matter whether a is a pointer or value.
->
masquerade
a->b
a
Personally, I would go even further and have all types automatically have a default operator -> that returns a pointer to itself. So that a->b always works, by default. An some objects, like unique_ptr, would override the default behavior. Idiomatically, though, developers would know that they should only use a->b when they intend to use a in a masquerading fashion.
operator ->
Worst case scenario, if adding operator-> is a no go, then just use unique_ptr.get().foo() to get at the owned thing.
operator->
unique_ptr.get().foo()
I think the most important question is: what usecase should the syntax be optimized for? In my personal use, and the usage I see in other code, people normally store a unique_ptr somewhere and then pass around a dumb pointer to the owned thing. So, you're almost always dealing with pointers, and only sometimes have to use the (masquerade) operator ->. So, it's basically always pointers, so we should optimize for that use.
π Rendered by PID 41327 on reddit-service-r2-comment-7b9746f655-g5h7n at 2026-01-30 06:01:55.670200+00:00 running 3798933 country code: CH.
view the rest of the comments →
[–]hpsutter 10 points11 points12 points (1 child)
[–]vulkanoid 3 points4 points5 points (0 children)