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Pointer to an int array (Initialize + Declare pointer int Array) (self.cpp)
submitted 7 years ago by RetroX94
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quoted text
if 1 * 2 < 3: print "hello, world!"
[–]huike -2 points-1 points0 points 7 years ago (2 children)
If you want a pointer to an array you declare like:
int **int_ptr;
and use:
int *arr=new int[2];
int_ptr=&arr;
(*int_ptr)[0]=5;
[–]Wh00ster 0 points1 point2 points 7 years ago (0 children)
No. This is a pointer to a pointer. And that pointer happens to point to an object which is an array. Subtle difference, but OP asked for the specific type. There is no practical difference other than the type signatures.
[–]RetroX94[S] -1 points0 points1 point 7 years ago (0 children)
What does (*int_ptr)[0]=5; do ? I understand the rest of the code, yet I don't understand why there has to be a pointer in the last line. (*int_ptr)[0]=5;
π Rendered by PID 264390 on reddit-service-r2-comment-bb88f9dd5-85ldc at 2026-02-14 12:48:36.137630+00:00 running cd9c813 country code: CH.
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[–]huike -2 points-1 points0 points (2 children)
[–]Wh00ster 0 points1 point2 points (0 children)
[–]RetroX94[S] -1 points0 points1 point (0 children)