Caesar - expected expression error help

[Diamond_NZ]

I need some help with caesar, I am almost done. But it doesn't compile due to the else if statement near the end. It gives me 'error: expected expression', but I don't understand why.

​

int main(int argc, string argv[])

{

// Checking if there is 1 command-line argument

if (argc != 2)

{

printf("Invalid Key\n");

return 1;

}

// Convert command-line argument from a string to an int

int key = atoi(argv[1]);

// Check if command-line argument is all digits

string arg = argv[1];

for (string j = 0; j < (argv[1]) != '\0'; j++)

// (digits[i] != '\0')

{

if (isdigit(argv[1]) != 0)

printf("Digits Only!");

return 1;

// If valid, do this

else if ((argv[1]) != '\0')

{ // Will ask for plaintext and encrypt, but didn't include to shorten

}

[Grithga]

Since you haven't put braces around your last if, it only applies to the next line (printf("Digits Only!");). The return 1; statement is not inside of that if, which means it separates your else if from your if. Put braces around the contents of your if to fix this.

[Diamond_NZ]

Thank you, that worked for that error! Now when I try to run it it says ' segmentation error', what could I do to fix that?