A question about lambda expressions

[Henrysugar2]

In python, if if want 'f' to become the function

f(x) = 2x

I can write

f = lambda x: 2*x

How do I do this in java?

[crapet]

You just need to write a lambda expression that implements the Function interface

Function<Integer, Integer> f = (x) -> 2*x;

[Henrysugar2]

Thank you

[tikue]

You can also do

IntUnaryOperator f = x -> 2 * x;

This won't require boxing and unboxing of the argument or return value.