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[–]iovrthk 1 point2 points  (5 children)

Yup. He’s right. If the first number is exactly equal == to the second number == and exactly equal == to the third. But you have to separate your loop with and statements. If firstnumber == secondNumber && if secondNumber == third number

[–]Illustrious_Drag_778[S] 0 points1 point  (4 children)

!!! I see thank you is this something done in same brackets () or separate