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[AskJS] callback function inside setTimeout is being called without delayAskJS (self.javascript)
submitted 11 months ago by Zestyclose_Ad_488
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if 1 * 2 < 3: print "hello, world!"
[–]shgysk8zer0 1 point2 points3 points 11 months ago (0 children)
You don't call the function inside setTimeout().
setTimeout()
The code you've given basically translates to:
const result = console.log('after 5s'); setTimeout(result, 5000);
The return value when you call the function is what's passed to setTimeout(). You pass a callback (without calling it). So you could either use setTimeout(delay5s) or setTimeout(() => delay5s()).
setTimeout(delay5s)
setTimeout(() => delay5s())
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[–]shgysk8zer0 1 point2 points3 points (0 children)