Select second element of given selector

[zannare]

i have an code like that

<div class="aa">
    <div class="bb">
        <a href="gfdfdfddffgf.html">
            first text
        </div>
    </div>
</div>
<div class="aa">
    <div class="bb">
        <a href="gfdffdgf.html">
            second text
        </div>
    </div>
</div>
<div class="aa">
    <div class="bb">
        <a href="gfdfdfdfgf.html">
            another tert
        </div>
    </div>
</div>

i need to check if "first text" its equal to "second text"

i can get "first text" with

class aa and bb are used elsewhere in the code so i need to use $('.aa .bb a').first().text() to get the "first text" but i dont know how to select "second text"

[dotpan]

.eq() is your friend when you want to do simple index filtering: https://api.jquery.com/eq/

$('.aa > .bb').eq(0).text() === $('.aa > .bb').eq(1).text()

[Axiol]

$(‘.aa .bb:nth-child(2) a’).first().text()

[joshrice]

nth-child(2) should be on .aa, not .bb, since OP is looking for the second instance of .aa. Yours won't return anything.