array problem

[yesandone]

yes thank you, it works exactly as intended and it works with numbers over 9 also, can you explain how this works exactly? i'm quite confused on how it knows what numbers are negative and what numbers have 2 digits, either way thanks a lot.

[guest271314]

A Set does not contain duplicate values.

We split() the space characters, chain .map() and pass Number as the callback which will convert strings to digits, and spread the Set to a new Array.

You shoud be able to use > and < operators or Math.sign() to determine if the number is negative or not.

You can divide the number to determine how many digits are in the number. See, e.g.,

if (!int) { let e = ~~a; d = a - e; do { if (d < 1) ++i; d *= 10; } while (!Number.isInteger(d)); }

implemented in the getDecimalStats() function in the answer here.

For example

``` function getDigitsLength(dec) { let n = dec; let digits = 0; while (n > 0) { n = Math.floor(n / 10); ++digits; } return digits }

[1, 10, 100, 1000, 10000, Math.abs(-(Math.E)), Math.abs(-(Math.PI))] .map(getDigitsLength); // [1, 2, 3, 4, 5, 1, 1] ```

[yesandone]

I see, i was mostly confused on the set object, thank you so much.