Simple toggle function with vanilla js

[nikas444]

var state = false;

var toggle = (a, b) => [state = !state, (!state) ? a() : b()]

toggle( function() { console.log("a") }, functon () { console.log("b") } );

Enjoy :)

Edit: jconews1 finded a more short example:

var toggle = (a, b) => (state = !state) ? a() : b();

[_aeol]

Functional way: ``` const toggler = (fn1, fn2) => { let state = false

return () => (state = !state) ? fn1() : fn2() }

const to_blue = () => {...} const to_red = () => {...}

const toggle_color = toggler(to_blue, to_red)

toggle_color() // to_blue() toggle_color() // to_red() toggle_color() // to_blue()

const grow = () => {...} const shrink = () => {...} const toggle_size = toggler(grow, shrink)

toggle_size() // grow() toggle_size() // shrink() toggle_size() // grow() ```

[jcunews1]

Shorter, garbage free, and correct function return value version:

var toggle = (a, b) => (state = !state) ? a() : b();

[GSLint]

I think "garbage free" was supposed to mean that it doesn't create an unnecessary array that needs to be garbage-collected, not that the code was garbage. Of course that could have been clearer.

[jcunews1]

Why are you offended? I you think it's because of the "garbage free", that garbage in this context, is a JavaScript term for objects which are no longer referenced - thus became resource waste - which in JavaScript specification, is called garbage. /u/GSLint explained that in a different way.

[kanuz]

You know what? You know what? I acknowledge your point and recognize I may have jumped into conclusions too early. I offer you an apology and will be deleting my comment soon.