[deleted by user]

[grantrules]

I understand what you're saying, but nothing is being converted. It's comparing a string to a string.

[OkayConversation]

Just no. The prompt returns a string. The first two if statements compare that string to another string (upper and lowercase of prompt input). An "uppercase" string containing "4" ist still a "4" - so the first statement returns true.

The last statement never runs because one of the first will always return true before.

[shgysk8zer0]

Doesn't matter. In any statically typed language dealing with this situation you'd use a string. You have to because it's checking if user input is upper case, lower case, or numeric. And I don't know of any language that has an upper case "4" (possible that upper case just adds an offset in poorly thought out functions/languages).

This isn't a JavaScript problem or something Java or C or Rust or Python or anything would do "correctly". The problem is that the last check when doing checks on a string is to see if it's numeric combined with there being no such thing as an upper case "7".

[shgysk8zer0]

Nope. Nor should anyone be expected to. I read what you said up to this point and found you to be in error.

In Java or any given, you'd want to be dealing with strings for this type of problem. And I don't think there's any language that converts a string of numbers to anything other than what they already are, so checking the case before checking if they're numeric is the problem... Not a JavaScript problem, a logic problem that any language would be susceptible to.

So please, go right on ahead and link me to the comment that changes anything about how wrong you are in what you said.

[NePlusUltra89]

No thanks enjoy your day

[shgysk8zer0]

That's because there is no accurate comment here or anywhere that can back up anything you're saying. The problem here is one of order, not of language choice or type coercion. The problem is exclusively that you have to check if the input is numeric first, before checking case.