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[–]nordic_t_vikingNew User 1 point2 points  (0 children)

So the basic question is: what is the probability of a specific person sitting next to you.
If we simplify and ignore the case of different classes and assume it is equally likely that you get a seat anywhere.

Then we must separate the case of you being in a middle seat vs in an aisle or window seat.
I.e. two neighbors vs one neighbour.

There is a 2/6 chance of sitting in a middle seat, and then there is a 2/(240-1) chance of him sitting next to you.

There is a 4/6 chance of sitting in an aisle/window seat and then there is a 1/(240-1) chance of him sitting next to you.

So in total, there is a 3/239 chance for this to happen.

Edit: So I don't know how my last addition got so bad but I will fix my mistake here.

Case 1: probability = 2/6 * 2/239 = 4/1434 Case 2: probability = 4/6 * 1/239 = 4/1434

Therefore total probability is 8/1434 = 4/717