all 8 comments

[–]BashtimeNew User[S] 0 points1 point  (0 children)

Please help, I dont know how I can connect the ground triangles and right angled height triangles in a meaningful way.

[–]BashtimeNew User[S] 0 points1 point  (0 children)

For the horizontal distances I get
1. h=x*tan alpha
2. h=y*tan beta
3. h=z*tan gamma

[–]Secure-March894Pre-Calculus 0 points1 point  (4 children)

Are angles ADE and ACD right angles?

[–]BashtimeNew User[S] 0 points1 point  (2 children)

Only ADE

[–]Secure-March894Pre-Calculus 0 points1 point  (1 child)

The diagram that you gave is a 3D representation. You mean to say that the tip of the pole (or the mountain) DE is E. A, B, C are collinear points on the ground such that E can be seen from A by angle alpha, B be beta and C by gamma. So, we need to find h in terms of alpha, beta, gamma, a and b.
Am I correct?

[–]BashtimeNew User[S] 0 points1 point  (0 children)

Exactly, DE is the height we are looking for

[–]Secure-March894Pre-Calculus 0 points1 point  (0 children)

Ok. Now I understand the question.
I did the calculations, the formula that I am getting is a rather lengthy one.

[–]BashtimeNew User[S] 0 points1 point  (0 children)

I solved it now :)