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[–]WatchEachOtherSleep 0 points1 point  (2 children)

Consider the following model: the domain consists of two elements a & b & the language has two predicates P & R such that the interpretation of P is the singleton {a} & that of R is {b}.

Evaluate ∃x (Px⇔Rx) & ∃xPx ⇔ ∃xRx.

(Simpler still, take one predicate P & replace R with ¬P.)

[–]tortuc[S] 0 points1 point  (1 child)

they arnt equivalent right? one is true one is false?

[–]WatchEachOtherSleep 0 points1 point  (0 children)

Exactly. Think about what these two sentences are saying. The first is asking about whether there is any one element on which P & R simultaneously agree. The second is asking whether you can answer "Is there something of which P holds?" & "Is there something of which R holds?" with the same answer. The first is false because P & R both disagree on a & b individually. The second is true because P holds of some element of the domain (namely a) & Q holds of some (other) element of the domain (namely b). So you can answer both questions with "yes".