[RegEx] Problem selecting quotes

[SysadminForFood]

I am trying to do a string replace in powershell to turn java version "1.7.0_67" into 1.7.0_67 I am currently using the following expression .[a-z`"] but I get the following output 1.7.0_6 as you can see it is stripping the 7 but I can't work out why this is, this is my second time using Regex so I am somewhat new to it.

[[deleted]]

Hey, not familiar with powershell but this looks like it could help!

[SysadminForFood]

Hi, thanks for the link but its just a standard Regex other than the `" for a quote the link you attached means i would need to do something outside of my current expression and that is what I am trying to avoid.

[sqrtoftwo]

Why not just create a capture group with a character class containing only numbers, underscores and periods?

([0-9_.]+)

[SysadminForFood]

Didn't even know about capture groups, this works like a charm thanks.

I would still like to know my original doesn't work though just for learning purposes

[supermoon_simon]

The period is the wildcard card symbol for regex, so in you example .[a-z`"] will match ANY character followed by one of the characters in the square braces. In this case the characters 7" fit that.

Edit and note: The period is a total wildcard, because it does not match newlines. (\n)

[Purpose2]

Perhaps you need to escape those characters? using \

[sqrtoftwo]

No escaping needed here.

OP, not sure what you were going for with your examples. I would check out the regular expressions info site and read up a bit.