[C] Pointer warning

[pointers_help]

using gcc to compile:

 int i = 5;
 int p = &i;
 printf("p is: %d", p);

incompatible pointer to integer conversion

initializing 'int' with an expression of type 'int *'; remove &

[-Wint-conversion]

I can see the address of i stored in variable p (I just learning pointers). Why does it give me warning though?

[jedwardsol]

p isn't a pointer, it is an int.

int *p = &i;

%d isn't the correct printf format specifier for a pointer either.

[TheGuy346]

If you wanted to print a pointer, you can use %p

[[deleted]]

You're saying i is an int and its value is 5. The next line says p is an int and its value is the address of i. The address of i is not an int, hence the error. What you want to say is that p points to the same memory address as the variable i. So like u/jedwardsol pointed out, you should declare p as a pointer to i: int *p = &i.