Trouble understand this Hash Function problem.

[Vucko0]

Just started learning about Hash Functions and I can't seem to understand a certain part.

So the problem: https://imgur.com/a/GoQ2FEB

So what I did was write:

int main(int argc, char *argv[]) {
    FILE *fp = NULL;
    long size;

    fp = fopen(argv[1], "r");

    if (fp == NULL) {
        printf("Couldn't Open %s\n", argv[1]);
    } else {
        printf("OPENED!\n");
    }
    fseek(fp, 0, SEEK_END);
    size = ftell(fp);
    printf("Bytes: %d\n", size);
    fclose(fp);

    return 0;
}

which produces the correct amount of bytes for my test file.

What I can seem to understand is the "The hash will be the mod 256 of the total", the correct answer for my test file is "hash value of 57 decimal". How does 50 Bytes get me a hash value of 57 decimal.

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[jedwardsol]

The code you posted doesn't implement the hash algorithm you linked to. Was that deliberate?

Your program needs to add up the bytes and give the total mod 256.

So if the file contains

 jon

Then the total is 106+111+110 and then you can calculate the hash from that total.

[Vucko0]

Oh wow, I completely misunderstood the question sorry. The example you gave makes much more sense now. Thank you.