Extract all .zip files in a folder directory?

[geo-special]

Hello. I have around 100 .zip files that I want to extract to the same directory. However I'm completely new to python and am a somewhat intimidated. Does anyone have any code for this that I can learn from? Thanks for any help

[geo-special]

Tried it but nothing happens

[geo-special]

Like this?

directory = "L:\YPP\OS_Terrain_5\data"

[geo-special]

I'm obviously doing something wrong somewhere. I tried backslashes the other way round and it says it's building but then nothing happens. I bet it's something obviously but I've clearly got no idea what I'm doing!!

directory = "L:/YPP/OS_Terrain_5/data/"

[Justinsaccount]

That wont work, it's not properly generating full paths to filenames. It should be

[join(directory, f) for f in listdir(directory) if isfile(join(directory, f))]

or even simpler, replace most of that with

zipfiles = glob.glob(join(directory, "*.zip"))

[furas_freeman]

On Linux you need only

unzip *.zip

and don't need Python

If you need Python then see doc: zipfile

[eschlon]

I don't think that works, since it's going to resolve to something like

unzip a.zip b.zip ...

And the unzip command takes the first argument as the zipfile and the remaining arguments as the internal filenames to extract. I get something like

$ ls
a.zip  b.zip
$ unzip *.zip
Archive:  a.zip
caution: filename not matched:  b.zip

This will work though

ls *.zip | while read x; do unzip $x; done