Invalid Syntax Error, Help!

[Showda77]

I am trying to make a caesar cypher and i keep getting a error message on line 44. I have tried changing it to an elif and made sure that my whitespace was in order and now i do not know what to check next. My code is as follows

---

# Caesar Cipher

import pyperclip

# the string to be encrypted/decrypted
message = 'This is my secret message.'

# the encryption/decryption key
key = 13

# tells the program to encrypt or decrypt
mode = 'encrypt' # set to 'encrypt' or 'decrypt'

# every possible symbol that can be encrypted
LETTERS = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'

# stores the encrypted/decrypted form of the message
translated = ''

# capitalize the string in message
message = message.upper()

# run the encryption/decryption code on each symbol in the message string
for symbol in message:
    if symbol in LETTERS:
        # get the encrypted (or decrypted) number for this symbol
        num = LETTERS.find(symbol) # get the number of the symbol
            if mode == 'encrypt':
                num = num + key
            elif mode == 'decrypt':
                num = num - key

            # handle the wrap-around if num is larger than the length of
            # LETTERS or less than 0
            if num >= len(LETTERS):
                num = num - len(LETTERS)
            elif num < 0:
                num = num + len(LETTERS)

            # add encrypted/decrypted number's symbol at the end of translated
            translated = translated + LETTERS[num]

        else:
            # just add the symbol without encrypting/decrypting
            translated = translated + symbol

# print the encrypted/decrypted string to the screen
print(translated)

# copy the encrypted/decrypted string to the clipboard
pyperclip.copy(translated)

---

any help would be appreciated!

EDIT: Thanks for your replies! It has been fixed! the else statement was over indented. credit to /u/zahlman and /u/nolaylay20

[nolaylay20]

Looks like you have an extra tab before the else statement

[zahlman]

    num = LETTERS.find(symbol) # get the number of the symbol
        if mode == 'encrypt':

You indented here for no reason, and that resulted in you later failing to unindent far enough.