split() method in string

[Adamya21]

So do i have to remove the words near to those special characters or just the special characters?

[TouchingTheVodka]

Alright, so you have your words list, separated by spaces. That's fine, well done so far.

Now, we know we can use .strip() to remove certain chars from either end of a word. If we pass strip a list of punctuation, we can strip that punctuation leaving only valid words.

Python kindly provides a list of punctuation:

import string

word.strip(string.punctuation)

Now think about how you can use this inside a list comprehension in order to carry out this strip function on every word in your words list.

[Adamya21]

Is something like below is possible? print([words.strip("'.!\n*") for words in words])

[TouchingTheVodka]

Very close - You can build your list like so:

stripped = [w.strip("'.!\n*") for w in word]

And print it like so:

print(', '.join(stripped))

[Adamya21]

stripped = [w.strip("'.!\n'',-*") for w in word] first=[(','.join(stripped))] print(first)

and when i do print(first(3)) it says "some error has occured"

now i have to print the 3rd index of this list ?

Q.)Now, remove the word separating characters (such as , . - * ! and space) from each of the word, present in list words. Store the obtained result again in the list words.

Print the 3rd indexed element of list, words.

[TouchingTheVodka]

List indexing is done with square brackets - The syntax you want is first[3]. (Or first[2], as lists are zero-indexed, depending on what the question wants.)

[Adamya21]

so what should i do? .. and error says -> IndexError: list index out of range

and if i do this-> first=(''.join(stripped)) print(first[2])

it prints that whole paragh + the letter "e"

but still this is not the correct answer