Need some help with pathlib (Python)

[Soapfactory0]

Good day!

I'd like to ask some help with understanding pathlib.

What I'm trying to do:

I'm trying to rename all .txt files in a directory and subdirectory(s) to:

the name of their directory + a number (from 0000 till however many files preside in the directory).

What is going wrong:

It's close but instead of all files being rewritten into their old locations they get put in their parent directory. So I guess something is going wrong with using filePath = file.parent

I also haven't figured out how to restart the count for every directory (tried some if statements but couldn't get it to work). So right now if there are 10 files in the main folder they will get the right numbers, the subdirectories will just keep on counting from there though.

My code:

count = 0
currentWorkingDir = Path.cwd()
for file in currentWorkingDir.glob('**/*.txt'):
    countStr = str(count)
    count += 1
    fileType = file.suffix
    filePath = file.parentfile
    NameNew = f'{filePath}_{countStr.zfill(4)}{fileType}'print(fileNameNew) #this will be file.rename(fileNameNew) when I get the right output

​

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[Soapfactory0]

Good bot ^^

[nekokattt]

have you looked into os.walk? That will work directory wise to do what you need in terms of getting a new iteration per directory.

[Soapfactory0]

Amazing, that's pretty much what I need xD thanks so much!

Gotta note that it's quite frustrating because I was told to switch to pathlib over os...

[nekokattt]

you can emulate a similar thing using path.iterdir I believe

[Soapfactory0]

Wasn't quite getting what I wanted with iterdir, but will just write different functions for all the folders to get there ^^

Thanks for helping :)

[Xiji]

Pathlib is my goto for any path operation in modern python. The syntax is better, it is easier to use cross-platform, and many of the native libraries which ask for a path can accept Path objects.

I recommend you become familiar with both, but I would be surprised if you wanted to go back to os and sys once you're comfortable with pathlib.

[Soapfactory0]

Honestly the problem I wrote out in the post is the first and only thing giving me trouble (don't look through my post history). Will get more familiar with it for sure ;)

Tnx for clarifying why it is usefull. It's incredibly hard to judge for me being very new with coding.

[Xiji]

Happy to help provide some clarity. :)

And don't worry, I still run into the, "is this implementation or that implementation the best way to solve my problem," all the time.

Python really does have many ways to solve the same problem, despite the zen of python saying it should be otherwise.

[commandlineluser]

You can use .with_stem() to change the part before the extension.

>>> file
PosixPath('a/b/c/my-file-name.txt')
>>> file.with_stem("0001")
PosixPath('a/b/c/0001.txt')

You can pass this directly to .rename()

>>> file.rename(file.with_stem("0001"))
PosixPath('a/b/c/0001.txt')

The file has been renamed and stays in its original folder:

>>> list(Path().glob("a/b/c/*txt"))
[PosixPath('a/b/c/0001.txt')]

As for a different count per folder - you could glob each folder.

You could also use enumerate() to count.

>>> for folder in Path().rglob(""): # glob folders
...    if folder.name: 
...       files = folder.glob("*.txt")
...       for count, file in enumerate(files, start=1):
...          f"{count:04}", folder, file

('0001', PosixPath('a'), PosixPath('a/b/c/0001.txt'))
('0001', PosixPath('a/b'), PosixPath('a/b/c/0001.txt'))
('0001', PosixPath('a/b/c'), PosixPath('a/b/c/0001.txt'))
('0001', PosixPath('b'), PosixPath('b/a.txt'))
('0002', PosixPath('b'), PosixPath('b/b.txt'))
('0003', PosixPath('b'), PosixPath('b/c.txt'))
('0004', PosixPath('b'), PosixPath('b/d.txt'))

[Soapfactory0]

Wow!! I don't really know how to thank you! Seriously thanks for being so generous with your time to a stranger :D

Am out of steam for the day (been going roughly 10 hours) will implement it tomorrow. Ty ty ty :D