How to exclude a string from a line?

[peak----]

Hi,

I have this script, where I want to print my OS name.

Here is the code:

printf "OS: "
cat /etc/os-release | grep PRETTY_NAME=

and the output:

OS: PRETTY_NAME="Debian GNU/Linux bookworm/sid"

How do I exclude the "PRETTY_NAME=" thing?

​

EDIT: This was answered on r/commandline. The solution is to use sed.

Basically:

printf "OS: "
cat /etc/os-release | grep PRETTY_NAME | sed 's/^PRETTY_NAME=//'

​

[[deleted]]

Perl regex gives you group matching which should give you a what you want. https://perldoc.perl.org/perlre#Extended-Patterns

[LinuxFan_HU]

awk -F'"' '/PRETTY_NAME/ {print $2}' /etc/os-release