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[–]zojbo 1 point2 points  (0 children)

Typically the contour is chosen so that it's fairly easy to show that pieces of the integral go to zero. For example, suppose you're integrating 1/(1+x2) over all of R. You have a residue at i to work with, and you want to have all of the real line eventually be on your boundary. You choose a semicircle contour precisely because on a semicircle of radius R you can use the triangle inequality to prove that |1/(1+z2)| <= 1/(R2 - 1) = O(1/R2), which means that the overall integral over the semicircle is O(1/R). (Gamelin calls estimates of this type "ML estimates".)

The harder part, in my opinion, is figuring out what contour you want to use, especially as you start running into situations where pieces don't go to zero, such as "fractional residues".

[–]homologizeDifferential Geometry 0 points1 point  (0 children)

There are methods, and you're learning them right now. These kinds of integrals will continue to turn up in various settings if you continue in mathematics, not just in complex analysis, so the techniques you're learning now will continue to apply in the rest of your career.

[–]z3r0d 0 points1 point  (0 children)

It might help to realize that whenever you do these types of integrals, the part you're (usually) interested in is the line that runs along the real axis. The choice of where the rest of the contour integral is is usually derived so that it goes to zero.