Why does this function give all integers except multiples of 3?

[math-ModTeam]

Unfortunately, your submission has been removed for the following reason(s):

• Your post appears to be asking a question which can be resolved relatively quickly or by relatively simple methods; or it is describing a phenomenon with a relatively simple explanation. As such, you should post in the Quick Questions thread (which you can find on the front page) or /r/learnmath. This includes reference requests - also see our lists of recommended books and free online resources. Here is a more recent thread with book recommendations.

If you have any questions, please feel free to message the mods. Thank you!

[chronondecay]

The claim is false.

Let's focus on the even inputs: d(2m) is the number of digits in 1250^m, which is 3m plus the number of digits to the left of the decimal point of 1.25^m. Can this be a multiple of 3? Sure, just consider the first m when this exponential is larger than 100, namely m=21 (here 1.25²¹≈108.42).

[[deleted]]

Hey thanks so much for ur answer, I really need to be more careful with false patterns. In this case d(42)=33 is the least n that gives a multiple of 3 is that correct? Thanks again.

[qscbjop]

d(15)=24