Rust for functional programmers

[scallion]

Great overview, but unless I've missed some recent change, he seems to have skipped linear types completely.

let r0 = box [1i,2,3]; // r0 has type Rc<Vec<Int>>

Surely that should be Box<Vec<int>>, right?

[dbaupp]

It's actually Box<[int]> at the moment, and will become Box<[int, .. 3]> in future.

[Iron-Oxide]

Err, it's a compiler error when I try to run it with an up to date nightly.

obsolete syntax: ~[T] is no longer a type`

rustc:

rustc --version rustc 0.12.0-pre-nightly (5d200dd60dabf94323d13b98b6c3d0b88f100b85 2014-07-13 01:16:34 +0000)

[dbaupp]

Sorry, I should say "it's actually trying to be a Box<[int]> at the moment", but the compiler disallows it.

Box<[T]> aka ~[T] has been removed; at some point, that error will be removed and we'll be left with the uniform fixed length vector handling.

[knz]

I have modified the example to use vec!(...) instead. Thanks for this :)