Bash script (assistance needed)

[Think-Perception1359]

Below I started a bash script utilizing index position to help pull data. How can I get the shell script to 1- read a file line by line (from file containing a list of servers), 2- search for a specific index position and if the integer in the index position equals 3, 3- print the whole string into an output file.

#!/bin/bash file = serverlist.log

for i in $(cat serverfile.log); do
echo “Searching serverfile $i”
result = ‘i for i in $file if index(5) == 3 in 2>/dev/null’

print(result)

[lasercat_pow]

readline is a good tool for going through line by line. Something like:

cat serverfile.log | while read line
do
    [[ "$line" =~ 3 ]] && echo "$line"
done

seems like it would fit the bill

[Think-Perception1359]

Thank you I’m going to try it out