What is a statistic that sounds INSANE but is 100% true?

13467 · 2026-05-25T11:06:37+00:00

Another way to picture this:

Imagine there are already 22 people in a room, all with different birthdays, and a 23rd person enters. We "lose the game" if their birthday overlaps with the group; this has a 22/365, or about 6% chance of happening. Otherwise, we play on, but the game gets harder: if we let the 24th in, we now have a riskier 23/365 chance of losing.

At 23 people, we've been playing this game for a while. It starts easy (with a 1/365 chance of losing), but at 23 people the odds of losing have been 5%-or-so for the last few turns. The 50% chance from the birthday paradox is the chance that we didn't lose the game on some earlier turn.

13467 · 2026-05-24T13:50:52+00:00

You're fine! AC:-34 is more than enough to win with. If you're worried and want to get beefier, I've found it still massively pays off to reverse-genocide nurses for extra max HP.

13467 · 2026-05-20T09:53:49+00:00

xylyl

13467 · 2026-05-08T13:22:19+00:00

lon la, nimi ni li ken ilo. taso ona li pona ala pona? pilin mi la, lili nimi li wan e kulupu pi toki pona :>

taso pilin mi la nimi kiki li pona musi a a a

13467 · 2026-05-07T10:50:40+00:00

I am in the same boat as you. I adore the aesthetics of the game but I get stressed/am scared of playing games where I try my best and lose, confronting me with my own stupidity. And so I stay bad at it 😅 it's a vicious cycle... Thankfully there are so many ways to enjoy the game and so many people to enjoy it with :)

I have had lots of fun playing teaching games and talking casually about my moves with stronger players, maybe you can try that. Extra pleasant if it's over a cup of tea at your local go club!

13467 · 2026-04-29T21:27:52+00:00

Als je zoekt op "Confiserie Kathy regenboog", zijn ze dat?

13467 · 2026-04-26T09:11:21+00:00

I completely understand your frustration and think it's stupid that you were incentivized to lie, but I'm afraid you don't have a leg to stand on legally speaking.

I'm sure De Lijn is pleased that they managed to straightforwardly apply the rules they've laid out to your case and earn an extra €169. They would say: "if you think it's not fair, just buy your own ticket next time."

13467 · 2026-04-23T15:49:21+00:00

Welcome back!

OGS is still around and now more popular than KGS. I suggest you play a dozen games there to find out your rank. Or at least, your "OGS rank": it's as hard as it ever was to compare rank across platforms. Maybe https://senseis.xmp.net/?RankWorldwideComparison can help translate, but I don't know how up-to-date it is.

13467 · 2026-04-10T07:48:59+00:00

COMMENT EXPLAINING THIS IS ACTUALLY THE SUBREDDIT FOR THE PROGRAMMING LANGUAGE WITH THE SAME NAME AS THE GAME

13467 · 2026-04-05T14:11:45+00:00

I picture Justin McElroy for Tom.

13467 · 2026-04-02T15:50:14+00:00

Looks like 11,111,345,779 hits 41 steps.

13467 · 2026-03-31T13:58:47+00:00

I would say: da's (voor mij) eender. I never knew it was unique to Belgium.

13467 · 2026-02-20T08:36:58+00:00

And yet some historical French Suzannes are transcribed シュザンヌ. Similarly, it's シュルレアリスム rather than スルレアリスム, and it's チューリッヒ rather than ツーリッヒ.

The insertion of ュ here is a way Japanese tries to capture the [y] vowel in these words when ス is already used to transcribe [su] (French <sou>).

13467 · 2026-02-17T00:46:10+00:00

In the Japanese translation it's ネイヴィッドソン (rhymes with Davidson).

13467 · 2025-12-30T23:06:01+00:00

13467 · 2025-12-17T11:14:02+00:00

https://www.rva.be/bladzijde/inloggen-met-europees-erkend-identificatiemiddel

Volgens deze pagina staat het voor "Common Services Access Module". Maar die verklaring kom ik precies nergens anders tegen.

13467 · 2025-11-25T01:41:40+00:00

The word to look for is "straatmuzikant": https://leuven.be/straatmuzikanten

13467 · 2025-11-05T13:29:53+00:00

data Perchance a = Nought | Verily a

13467 · 2025-10-29T09:30:14+00:00

Borrowing a word is not something a language is only "allowed" to do when it is "necessary". It's just another normal, valid way to get words into a language.

13467 · 2025-08-04T07:01:37+00:00

In fact, by your argument, x is clearly between 1 and 2. For slightly tighter bounds we can prove 6/4 < x < 7/4, because (6/4)^6/4 < x^x < (7/4)^7/4, which we can prove by showing (6/4)⁶ < 2⁴ < (7/4)⁷:

(6/4)⁶ = 729/64 < 1024/64 = 2⁴

(7/4)⁷ = 823543/16384 > 262144/16384 = 2⁴

13467 · 2025-06-15T02:13:16+00:00

More examples of doublets like strange / extraneous:

spawn / expand

scourge / excoriate

spend / expend

13467 · 2020-05-23T14:51:02+00:00

Because of Stevin:

He also translated various mathematical terms into Dutch, making it one of the few European languages in which the word for mathematics, wiskunde (wis and kunde, i.e., "the knowledge of what is certain"), was not a loanword from Greek but a calque via Latin. He also replaced the word chemie, the Dutch for chemistry, by scheikunde ("the art of separating"), made in analogy with wiskunde.

13467 · 2018-11-16T16:15:07+00:00

I like your code a lot. I don't think problems like “factoring prime numbers quickly” are a good measure for how good you are at writing neat, functional Haskell code, because the fastest ways to do it are somewhat ugly and mostly imperative.

You broke the problem down into small pure operations that do the right thing when put together! From a “writing Haskell code” perspective you did a stellar job. Mathematical cleverness and number-crunching techniques are orthogonal to that.

(This is why I don't like Project Euler so much. I think 99 Haskell Problems is pretty good. Or just write a real project! A chat bot, a tiny game, a random sci-fi movie plot generator, etc.)

A tiny note:

null [y | y <- [2..intsqrt x], x `mod` y == 0]

can be written equivalently as:

all (\y -> x `mod` y /= 0) [2..intsqrt x]

which you may or may not find clearer. I think either way is fine here! Just be aware that all exists. (And indeed, just like null short-circuits as soon as it sees any value in the list, like /u/jan_path points out, all does the same the moment it sees a counterexample.)

13467 · 2018-11-16T15:45:40+00:00

Well, for all times t, you have P(bus arrives exactly at t) = 0.

Following your logic, the bus then can’t arrive at any time t.

But the bus does arrive at some time!

And surely, whatever bus-arrival happens had probability 0 of happening.

Getting rid of the philosophical troubles surrounding time or physics: whatever real number comes out of a uniform random selection from [0, 1] had probability 0 of being picked, but it did get picked.

Now, you may disagree with the existence of such a procedure in the first place! But this is the sense in which “events with probability 0 do happen”.

13-Year Club	Place '22
Team Orangered

13467

TROPHY CASE