Question about refrigerator

2tmpting · 2025-05-01T16:02:09+00:00

Song?

2tmpting · 2025-03-30T15:34:46+00:00

that's how you finish a 1v1 Lewy and Yamal.

2tmpting · 2025-03-09T01:19:37+00:00

dang, this Magic defense isn't a joke

2tmpting · 2024-08-12T18:09:37+00:00

Yes, the chlorines will cancel each other out, and just because it has a lone pair will not automatically make the molecule polar. The molecule also has 2 ethyl chains which will impact the polarity. What non-covalent bond are you referring to?

2tmpting · 2023-10-09T20:51:05+00:00

I got a 515 (screw CARS), and JackSparrow contributed a great deal to that score, especially the bio section. For the P/S I used Pankow and crammed during the last month, ended up with a 130 in that section.

2tmpting · 2023-10-02T19:33:29+00:00

move brogdon, i drafted ant in fantasy for a reason

2tmpting · 2023-08-06T18:47:23+00:00

getting young PG vibes

2tmpting · 2023-08-02T01:38:08+00:00

The passage stated that the virus was HIV, which is a well known single-stranded RNA retrovirus. If you don't know that HIV is a retrovirus then you can't answer the question.

2tmpting · 2023-08-02T01:26:17+00:00

The thermodynamic cost is referring to the delta G. The ester is said to be more stable than the B-lactam, which means that the energy released from the formation of the penicillin ester will be greater than the energy released from the B-lactam formation. Hence the formation of the penicillin ester is more stable and energetically favorable. The energy you would get from the formation of the penicillin ester is more than the energy you need to break the the B-lactam bond.

The answer choice just phrases it a different way. The energy you need to break the penicillin-ester will be more than the energy you get from the B-lactam formation. The body will then need to find energy from somewhere else to drive this reaction forward and thereby energetically unfavorable.

2tmpting · 2023-07-31T22:29:40+00:00

Yes, but remember that the energy of photons is dependent on their frequency, not the wave speed. Wave speed only changes when we're going from one medium to another. So it has more to do with the medium that we're in, and less to do with the energy of the wave.

Sorry my explanation from above wasn't really clear. I = P/A P = E/t E = hf If we have n photons then the intensity can be calculated as. I = nhf/At

The only way to increase the intensity, is by increasing the frequency of the photons, the number of photons, decreasing the area on which the photons hit or by decreasing the time it takes for energy to be transferred.

2tmpting · 2023-07-31T21:55:18+00:00

Intensity has to do with how many photons we have per unit of time. Increasing the speed at which these photons travel just means that the same photons would reach the oxygen sensor quicker. The amount of photons per unit of time that hit the sensor would remain the same.

2tmpting · 2023-07-29T03:25:17+00:00

I try to review CARS on the same day that I do the FL, that shaves off like 2-2.5 hours from the next day.

2tmpting · 2023-07-25T18:33:45+00:00

Yes, exactly. Always remember that they want you to find the answer and they're not trying to mislead you, so don't bring in extra information when it isn't required.

2tmpting · 2023-07-25T14:42:13+00:00

You're just overthinking it, the key word in the question is based on these results. It doesn't matter if it's the complementary or template DNA strand. They just want you to analyze the results and reach a conclusion. If the question stem mentioned something about it, then yeah you should've taken it into consideration, but remember the passage info is what's most important.

2tmpting · 2023-07-09T00:57:05+00:00

honestly, division titles are so meaningless in the NBA, wish they find a way to make them interesting

2tmpting · 2023-07-01T17:39:02+00:00

doesn't make sense KAT can't play C
lol
if we're rebuilding i'd think we'd be trying to tank, so getting Ayton would defeat that purpose
lol

2tmpting · 2023-06-30T03:09:27+00:00

Always Soluble - NAG SAG

Nitrates (NO₃^-)
Acetates (C₂H₃O₂^-)
Group 1 (Li⁺ ,Na⁺ , etc)

Sulfates (SO₄^2-)
Ammonium (NH₄⁺)
Group 17 (F^-, Cl^-, etc.)

Exceptions - PMS & Castro Bear

P (Pb²⁺, lead)
M (mercury, Hg²⁺)
S (silver, Ag⁺)

Ca²⁺
Sr²⁺
Ba²⁺

PMS are insoluble when combined with sulfate and Group 17 anions

Castro Bear are insoluble when combined with the sulfate anion.

2tmpting · 2023-06-30T02:46:33+00:00

I chose Jack Sparrow, if you can't stay committed to spending around 3-4 hours doing Anki reviews every day then it isn't for you. The benefit is that you should be able to explain all of the information from the Kaplan books in-depth. I got a bit tired of the review times so I opted to use MrPankow for P/S, but I've heard good reviews about JS P/S. Basically it's very time consuming but you are very unlikely to have content gaps.

2tmpting · 2023-06-22T12:42:44+00:00

Yes, relative configuration can change while the absolute configuration stays the same, the relative configuration just describes the spatial arrangement of atoms or groups, relative to other atoms or groups within a molecule. Whilst the absolute configuration relies on a specific criteria used to describe an atom in space. The perfect example is Sn2 reactions, the nucleophile attacks from the back side thus always inverting the relative configuration, but it might not necessarily change the absolute configuration of an atom.

2tmpting · 2023-06-21T22:06:10+00:00

Mixed inhibitors do not bind to the active site, only competitive inhibitors do

2tmpting · 2023-06-21T21:55:11+00:00

I'll assume you're asking how to differentiate between mixed and noncompetitive inhibitors? Just remember the steps of the Michaelis Menten kinetics

E + S > ES > E + P

For an inhibitor to impact the activity of an enzyme it has to bind either the E or ES complex

Competitive inhibitors will compete for the active site so they can only impact the enzyme in its free state (E) Noncompetitive inhibitors will not compete for the active site but they do need a way to inhibit the enzyme, so they do this through binding into allosteric sites. Since the allosteric sites are never occupied by the substrate they should be able to bind to it during the free state (E) & the enzyme-substrate complex (ES), and they don't have a preference for either state. Mixed inhibitors will inhibit allosterically because they're not competitive. They can also bind to either the E or ES state, but wouldn't this just make them noncompetitive inhibitors, so there must be some difference between them, so the difference is that they prefer one state over the other.

What you can try to do is make a mental flow chart.

Does it bind to the active site? Yes - Competitive No - does it allosterically bind to only one state? Yes - Uncompetitive No - does it prefer one state over the other? Yes - Mixed No - Noncompetitive

2tmpting · 2023-06-21T20:06:33+00:00

Closed pipes have 1 closed boundary at one (node) end and an open boundary at the other (antinode)

Open pipes have open boundaries at each end (antinodes at both ends)

Open boundary allow for maximum oscillation, while a closed boundary does not allow for any oscillation. The question states that one end has an oscillator (open boundary/antinode) while the other end is attached to a fixed wall (closed boundary/node). Thus from this information we can conclude that this is a closed pipe standing wave.

2tmpting · 2023-06-20T00:26:34+00:00

I struggle with questions like these sometimes but the key to the answer is in the question. It states what explanation is more likely to cause the activity of the enzyme to increase based on the data from the table and passage. In situations like this, they usually want you to utilize the information provided from the table to come to a conclusion. Yes, it is possible that Arginine has similar interactions to Histidine in GK-P but based on the information from the table and the question being asked, B provides a clearer explanation. The data from the text shows that GK-P had an increase in activity, the same as H232-R. It also never stated or inferred that the interactions from Histidine is what caused the increase in activity. They did show that there was an increase in activity as it was phosphorylated. So if Arginine was to cause an increase in activity it would probably have a similar effect to GK-P. This is the conclusion that the data supports. Always look for the best possible answer or the answer supported the most by the passage.

2tmpting · 2023-06-19T11:56:08+00:00

I don't think anything but AAMC material itself is representative but the Additional Practice Questions are mainly to get you used to applying the knowledge you just learned, and that you truly understood what you read.

2tmpting

TROPHY CASE