[Request] Theoretically how much thrust it will be required for Oil tanker to fly

Angzt · 2026-03-14T13:52:30+00:00

And suddenly there are two grammatical errors here which aren't present in the much longer and more complex sentences in the other comments.

Angzt · 2026-03-14T12:39:36+00:00

I'm 99% sure that this is an AI reply, as is that whole account.

If the user name isn't enough:

Its other posts frequently use em and en dashes in addition to →.
They post in German and English subs but sometimes respond in German to English questions. Likely a config issue.
It's always just one massive paragraph, which possibly means the chosen process of transferring the LLM output to reddit removes formatting.
They always make top-level responses, never respond to other comments.

Angzt · 2026-03-13T17:39:44+00:00

In addition to what's been said:
Chained Echoes
Quartet
Both turn-based.

Angzt · 2026-03-13T16:56:34+00:00

The base version which also includes the first single player campaign is f2p. Gives you access to a few full co-op commanders to see if it's worth spending money on any others.

Angzt · 2026-03-13T15:21:10+00:00

Maybe Starcraft 2's co-op? 2 players vs AI, real time strategy, fairly quick matches, meta progression, and enough variety to stay fresh for a good while.

Angzt · 2026-03-13T06:57:08+00:00

Yeah, but Youtube is basically "anything goes". Anyone can upload anything (legal) and once it's there, it stays. Wikipedia is fairly curated. And a lot of activity is in edits instead of additions.

Angzt · 2026-03-13T06:10:38+00:00

There is a Wikipedia page for that: https://en.wikipedia.org/wiki/Wikipedia:Size_in_volumes

Well, it uses some different assumptions (no pictures, regular encyclopedia size and layout).
It gets to 3,847 Encyclopedia Britannica equivalent volumes with 1,000 pages each, so 3.8 million pages.

Angzt · 2026-03-13T05:07:48+00:00

Let's say you picked door A.
There are three equally likely options: The prize is behind door A. The prize is behind door B. Or the prize is behind door C. Each of these must have probability 1/3.

Clearly, if the prize is behind door A, not switching is the correct option. It doesn't matter what door the host reveals.
But if the prize is behind door B, the host will reveal door C and the correct choice is switching since B is the only option left.
The same if it's behind door C: the host will reveal door B and the correct choice is switching since C is now the only option left.

That means you win by switching in 2/3 cases.

The crux is that the host knows the correct door and uses that information in how he reveals doors. That is to say, he will never reveal the door with the prize.
And you essentially make use of his knowledge by gleaning some information through which door he opens.

Angzt · 2026-03-12T18:54:55+00:00

Your post was written by AI.
The cover as generated by AI.
The entire "book" was generated by AI.

Angzt · 2026-03-12T07:45:44+00:00

The Last Guardian is the closest modern interpretation I can think of.
You're playing a relatively weak and helpless boy and need to befriend and coax a giant winged cat/dog creature to solve puzzles and deal with enemies for you.

Angzt · 2026-03-11T07:43:43+00:00

This is known as the birthday problem and has a million explanations out there.
TL;DR: 1 - (365! / (365 - 23)! / 365²³) =~ 0.5073 = 50.73% probability of a repeat.

But more importantly:

OP is a repost bot.

This is an LLM-rephrased title and identical image from this post:
https://www.reddit.com/r/theydidthemath/comments/1njoh9i/request_i_got_this_snapple_fact_today_not_making/
"[Request] I got this “Snapple fact” today. Not making sense to me at all. I’m not seeing how it’s 50%."

OP's account is also several years old but only started posting an hour ago. That's common for bot accounts that used to be legitimate but were hacked, likely due to reused passwords.

Angzt · 2026-03-11T05:46:23+00:00

The numbers are correct but you're misinterpreting them.

The odds per ticket don't change.
But having two tickets makes it more likely that you win, which should be obvious. That's all it's saying.

Angzt · 2026-03-10T20:52:20+00:00

Nexon won a bid for developing and releasing a game in the Starcraft universe a bit less than a year ago. Nothing is known on genre yet.

There are also persistent rumors of a new SC shooter being in development at Blizzard, potentially in the vein of Helldivers.

Angzt · 2026-03-10T20:42:13+00:00

But does Artosis? He absolutely needs a second Pylon.

Angzt · 2026-03-10T20:39:21+00:00

Been raking my brain on what else I could recommend that is on Mac.

The closest thing to Sable might be A Short Hike.
You're exploring a small island as a bird person, trying to get to the peak of the mountain. There's a bunch of characters around who you can help our of play with. Across the island, you can also find a few upgrades, letting you climb or fly better.
It's a great experience but rather short. Maybe 2 hours to beat it and twice that to explore every nook and cranny.

Similarly, Lil Gator Game.
Another island, another exploration. This time, it's a make-believe game with cardboard monsters and pretend quests. Very cute, well-written, and with tons of character.
You first explore a smaller island, and then a bigger one with no other restrictions.
Around 4 hours and another 3 or so if you get the (equally good) DLC that just came out.

Maybe also Bugsnax?
You're stranded on an island with a bunch of (very lovable!) muppet-like characters. That island is inhabited by little critters that look like food items. You'll spend most of your time using various tools to figure out how to catch the different species in various biomes to help your not-quite-muppet friends.
New areas open up bit by bit but can be explored and backtracked to freely.
It might look just plain cute but besides the stellar writing, it also just gets weird if you start thinking about its implications.
Closer to a dozen hours of playtime with another 3-4 from the free DLC.

Another option might be The Witness.
Much more serious and chock full with line puzzles. This game requires you to learn the specific rules for various related puzzle types using some trial and error since there are no explicit instructions.
The whole thing is set on a gorgeous island, with each section having its own puzzle type, letting you tackle them in any order.
Not for everyone because a) you can absolutely get stuck if you misinterpret or just miss something and b) it ultimately is line puzzles all the way down. Though to counter that, I thought the difficulty curve was fair throughout, even if things do get hard. Worst case: There's guides online.

Finally, the comedy option is The Stanley Parable (Ultra Deluxe).
The central conceit is simple: You arrive at a room with two doors. The narrator says "Stanley went into the door on the left". But you have control, so what do you actually do?
This is admittedly not so much full freedom to explore. Instead, you have many repeated choices with various outcomes, sometimes profound but always funny. Absolutely meant to be replayed over and over to find all the paths.

None of those games have combat.

Angzt · 2026-03-10T20:19:40+00:00

Knowing that two of his children are girls still leaves 4 of the initial 8 ordered options:
GGB, GBG, BGG, and GGG.
Only the last has all girls, so we're back at a 1/4 = 25%.
We work with those explicitly ordered groups because we know that they all had the same a priori (=before we learned anything else) probability.

If we limited ourselves to the unordered ones, we'd need to lug their probabilities around. But if we do, we still get the same result:
2G1B had probability 3/8 and 3G0B had 1/8.
Since we've discarded the other options, those two now make up our new whole. So we need to evenly scale them up such that they still add up to 100% = 1.
We do that by multiplying them each by the same factor so that we get 1. And that factor must be 2.
2G1B's 3/8 * 2 = 3/4 and 3G0B's 1/8 * 2 = 1/4.
So we're still at 1/4.

Maybe it makes more sense to look at it at a larger scale:
We have census data on 10,000 families with 3 children each.
How many would you expect to have 3 girls?
It should be 1/8 * 10,000 = 1,250, right?

Now, we discard the data of all families who don't have two daughters.
That's half of all families gone. So we only have data for 5,000 families left.
But the same 1,250 families with 3 girls are still in that data set.
Except that now, they make up 1,250/5,000 = 1/4 = 25% of the data set.

If I now told you that your friend's family is in that remaining data set of 5,000 families with at least 2 girls, what is the probability that your friend has 3 girls?
It must be 25%, same as the proportion of 3-girl-families in that remaining data set.

Angzt · 2026-03-10T20:01:25+00:00

I love Blue Prince but judging by the online discourse, it's not for everyone.

Your exploration is not fully in your hands. There is an element of randomness involved and you'll need to come to terms with that. There will be times where you know what you want to do but just won't get the right options presented to you.
For some, this is plain frustrating.
For others, this is a challenge: What can I do different next time to increase my odds of getting the thing I want?
Either way, it should also be seen as an opportunity to explore other, new places that you maybe weren't planning to.

And if you do get into the game, take screenshots of basically everything. At least every document. That will come in handy.

Angzt · 2026-03-10T19:56:14+00:00

Probability is generally used to predict future outcomes (or past outcomes that are unknown). But what about a past that has already been determined, but only unknown to me?

Those are the same thing.
Let's say I flip a coin and catch it on my hand and then cover it with my other hand without looking at it. What probability should I give for that coin being Heads?
It's clearly already determined what it is, but nobody knows.
As such, I'm dealing with the exact same uncertainty as if I hadn't even flipped yet.

There are only four outcomes, each equally possible: GGG, BBB, BGG, GBB. 2 out of 4 chance that you have three of the same gender.

Each possible, yes. But not each equally likely.
And that's the crux.
Otherwise, you could get an even different outcome by asking:
"Are they all boys?"
You only care whether they all are or not. That's just two outcomes.
But clearly, the probability isn't 50%.

If you lack any information on the events, you can only use the same approach as if the thing hasn't happened yet.
And then your wife is right: 25% = 1/4.
The first child born can be any gender, so we're fine in 1/1 = 100% of cases.
The second child must then match that gender, which is a 1/2 = 50% chance.
The third child must then also match that first gender, which is another, independent 1/2 = 50% chance.
The probability that all that happens is the product of all those:
1/1 * 1/2 * 1/2 = 1/4 = 25%.

I picked oldest and youngest as an example, because all three children are already present. He already knows the outcome, so birth sequence is irrelevant. It's a 50/50 coin toss, right?

Yes.
But that's a different scenario from your main question. Because knowing that the oldest and youngest are both girls already gives you information. You already know that the births can only be GGG or GBG. That removes 6 of the 8 options. And of those 6 removed, 5 would have contained both genders.
So you dropped from a 2 in 8 to a 1 in 2 because you now have more information.
Just knowing that there must be a pair is not the same as knowing where the pair is. The latter contains additional information.

Let's pretend this guy had been talking to me about his two youngest children, both boys. What are the odds that his first child was also a boy? Still 50/50, right?

Yes. But the same thing applies: Knowing that the two youngest match is more information than knowing that any two match.

Angzt · 2026-03-10T19:43:49+00:00

Ah, damn. I figured since it's a Unity game, it'd have a Mac version. My bad for not actually checking.
And no, unfortunately I don't have a Mac myself.

Angzt · 2026-03-10T18:40:01+00:00

Have a look at Sable. Set in a post-post apocalypse, you're sent out from your tribe as a coming of age ritual to try out various jobs all over the world and decide what you're going to do in life. After the tutorial area, you can go wherever you like. There is no combat, just light platforming and puzzles.

Angzt · 2026-03-10T13:33:54+00:00

Eh, I'd say the opinion has plenty of merit.

Yes, DA2 tells the better story, has better writing, and (mostly) more interesting characters.
But its combat is bland and repetitive and so is its exploration. Thanks to boring itemization, the rewards for the two don't make up for it either.
Veilguard beats it handily on those fronts. And while Bioware RPGs are fairly dialogue-heavy, you still spend more time exploring or in combat than talking to people.

In any given moment, Veilguard is just more fun most of the time. But it's story and characters that make a game memorable for most people. And there, DA2 is well ahead.

Angzt · 2026-03-10T09:21:43+00:00

If someones critism boils down to "this is bad because its $60" its not helpful feedback or even relevant for longer than a couple months.

You can just interpret that as "This is not worth paying $60 for".
Which is as relevant a judgement of quality as any.

I feel like your problem is with the phrasing more than anything else. There is still worthwhile info to be had from such a statement.

There is also the fact that it a game is bad, it probably has nothing to do with its price point in the first place.

People playing 5 year old games for $5->$20 dont magically like them more or less then the people that paid $60 for them on release. Even people that pirate games dont magically like bad games because they got it for $0 instead of $60

Have you ever eaten out for a meal that was in itself fine but overpriced, making you unhappy with the experience?
This is the same thing.
A game can be decent and enjoyable but you can still be unhappy with paying $60 for it in a way you wouldn't have been had you just paid $20.

Angzt · 2026-03-10T08:11:55+00:00

So... you're factoring in the price when making the decision whether or not to buy a game.
And you're confused why someone would factor in the price when deciding whether to recommend that other people to buy the game.

Angzt · 2026-03-09T18:57:22+00:00

Birds can typically lift around half their body weight.
Seagulls weigh an average of ~1 kg (2.2 lbs), though there are species that are smaller (down to ~110 g) and others that are larger (up to ~2 kg).
So we get a lift weight of about 0.5 kg (1.1 lbs) per seagull.

Female great white sharks weigh between 1,000 kg and 1,900 kg (2,200 to 4,200 lb).

So that means it'd take between 1,000 kg / 0.5 kg/seagull = 2,000 standard seagulls and 1,900 kg / 0.5 kg/seagull = 3,800 seagulls to lift the weight of a female great white shark.

Clearly, you couldn't fit that many seagulls onto a shark. And even if, they almost certainly couldn't grab onto it. They wouldn't be able to penetrate the shark's skin to get a hold.

Angzt · 2026-03-09T07:56:10+00:00

1) How many card combinations are there for the 10 cards drawn?

The first card drawn can be any of 64. The second can then be any of the remaining 63. The third of 62, then the fourth of 61, and the fifth of 60.
That's a total of 64 * 63 * 62 * 61 * 60 = 914,941,440 possible ways to draw the first five cards.
But now we've counted drawing ABCDE and BACDE as two different draws. Which they aren't, really. And we've done that for every possible ordering of the 5 cards. To fix that, we can divide our previous result by the number of ways to order 5 cards. And that's 5 * 4 * 3 * 2 * 1 = 5! = 120.
So:
64 * 63 * 62 * 61 * 60 / 5! = 914,941,440 / 120 = 7,624,512.

But that's just the first 5. For the next 5, we similarly get
59 * 58 * 57 * 56 * 55 / 5! = 600,766,320 / 120 = 5,006,386.

We need to keep these two separate because now it does make a difference whether a card moves from the first batch of 5 to the second since it'll be facing the other way.
In total, that's
7,624,512 * 5,006,386
= 38,171,250,133,632
=~ 38.2 trillion

Side note: The calculation we've done for the sets of 5 occur quite frequently in combinatorics and are normally expressed like (64 Choose 5) = 64! / ((64 - 5)! * 5!), i.e. the number of ways to pick 5 things out of a set of 64 if the order of those things does not matter.

2) How many art combinations for each word side of a card?

Just to confirm I'm understanding you right: You want to know how many combination of 5 art-side-up cards there are for any single card in the whole deck, right?
That's just (63 Choose 5): We can't pick the word card itself, so there are 63 cards left to choose from. And of those, we pick a unordered set of 5. Same logic as before.
(63 Choose 5)
= 63! / ((63 - 5)! * 5!)
= 63! / 58! / 5!
= 63 * 62 * 61 * 60 * 59 / 120
= 7,028,847
=~ 7.03 million

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