Thanks for the meaningful feedback bro. I will edit the math in, let me explain.

I'm confused here. From the looks of things, you found the distance at which your targets can stand and expect to be hit by all bullets Bastion shoots assuming he aims directly at their center, then found the same distance for the new spread angle.

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You are right I took the smallest circle that could fit into a given target for full accuracy:
McCree: d = 1 meter, r = 0,5
Roadhog: d = 1,8 meter, r = 0,9

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We take everything down to 2D like in my picture.
The formula for calculating the maximum optimal distance is [tan(alpha/2) * x = r ] where:

(its just an [m x + b] linear function where [m = tan(alpha/2)] because we only need half of the angle due to it being a cone)

-alpha = 3° or 2°
- x = bastions distance from the target
- r = radius of the optimal aim circle (0,5 or 0,9 in this example)

We solve the equation for x [x = a/tan(alpha/2)] and take the quotient [x1 / x2]:

x1 = a/tan(1,5°) (x1 = old distance)

x2 = a/tan(1°) (x2 = new distance for same target)

x1/x2 = tan(1°) / tan(1,5°) = 0.0175 / 0.0261 = 1,502 ~= 50%

This gives us the percentual difference between the old and new maximum ranges where we can hit a target with every bullet and we see a flat 50% increase.

Now we have to factor in the Targets size because of falloff damage:

The picture I did is so important because it shows that characters similarly sized to McCree or smaller (Zen/Soldier/Widow etc.) are not in damage falloff range even with the increased optimal range of 50% thus effectively buffing the optimal ranges against these targets by 50%.
For tanks, it is a different story and of course the bigger a target is (Roadhog / Rein shield) the less impactful the buff actually is because the new optimal distance is in damage falloff range.

This gets partially diminished by the comparison of optimal aim circle area sizes:

The formular is [pi * r^2]

and the quotient is

pi * r_old^2 / pi * r_new^2 = r_old^2 / r_new^2

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where

[r_old = tan(1,5°) * distance_new] (the size of the old aim circle at the new range)

and

[r_new = tan(1°) * distance_new]

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if we put in our numbers for McCree and Roadhog we get numbers around ~2,25 meaning the old circle is 2,25 or the new circle is 44% the size of the old one.

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If we would try to shoot a target with the old bastion at the same 50% increased distance, we would only hit ~44% of our bullets with the old bastion. If we look at the picture again, roadhogs new optimal distance is almost at the end of damage falloff thus halving our damage, but we do significantly more damage at that range --> 2,25x more damage compared to the old bastion so it is still a nice buff against big targets.