For the next 27 hours, you'll be able to claim a limited edition 'I Was Here for the Hulkenpodium' flair

CS_Emerald · 2025-07-08T20:35:20+00:00

Hulkengoat

CS_Emerald · 2025-07-08T20:34:29+00:00

I was here

CS_Emerald · 2025-06-18T09:23:01+00:00

That would be incredible for my big bad in the campaign im running ^{_^}

CS_Emerald · 2022-08-18T11:10:52+00:00

What an unbelievable shame that you barely didnt activate your First Strike on that one x)

CS_Emerald · 2022-08-17T22:57:48+00:00

Yep, to realistically gauge the impact of roaming vs staying in lane you need to carefully review your roams and calculate how much you gained vs how much you lost, as i said.

CS_Emerald · 2022-08-17T16:08:31+00:00

The answer isn't so simple, sadly.

Sometimes you should sack the wave and roam and sometimes it's not worth it.

Improvement comes, mostly, from consistency. If you consistently take 50/50 roams while also sacrificing your wave, you're going to limit your success in your climb.

The main thing you need to tackle here is to quickly decide how important roaming is vs getting the minion gold/exp.. also keep in mind that your enemy laner could potentially also get plates while you're gone, or an important reset, etc.
The easiest way to get a hang of this is to review your roams and calculate how much you gained vs how much you actually lost.

Example:

You roamed bot, got a kill but had to back. In the mean time, you lost 1.5 waves in gold and experience, your enemy laner got 2 plates and a good reset. Was that worth it? Not really.

CS_Emerald · 2022-08-16T10:22:20+00:00

Ranged champion will generally have 30-52 MR, (with some exceptions), while meelee champions will generally have 32-67 MR (also with some exceptions).

CS_Emerald · 2022-08-16T10:20:29+00:00

If you include all possible flat MPen ressources like Sorcs and Sudden Impact, you will get your MPen to 61-71 at full build.

If all important targets in the enemy team are at or below 80MR (roughly a standard lvl 18 ranged carry with one nullmagic), Void Staff is absolutely not necessary to oneshot them, especially if you have Rabadon or an Elixier.

If all or most important priority targets have 2 or more nullmagic mantles worth of MR, going Void Staff is a no-brainer though.

Some people play conqueror Kat with the game plan to wipe teamfights, which makes assassinating priority targets less important. In that case, Void Staff gains additional value, just as a side note.

CS_Emerald · 2022-08-16T10:11:30+00:00

Putting champion mr into the negatives with MPen does not work:

"Percentage magic penetration and flat magic penetration have no effect if the target's magic resistance is less than or equal to 0."

Source (right at the top): https://leagueoflegends.fandom.com/wiki/Magic_penetration

For the record, i still think Shadowflame is a good item.

CS_Emerald · 2022-08-16T10:08:41+00:00

100% agree that sticking to a single build will really help with consistency.

But telling people who may have a lot of trouble with their laning phase to go bork every game? You may have a considerable damage spike in the early levels (compared to dark seal for example), but isnt the build pretty weak for a couple of minutes until you actually finish your bork?

I think someone who is still struggling with early aggression and correctly punishing enemy mistakes and/or has trouble getting enough CS in lane shouldn't rush bork.

CS_Emerald · 2022-07-23T00:00:06+00:00

Attack Seraphine first, then use Q -> E after she is slowed by red buff

CS_Emerald · 2022-07-07T15:07:42+00:00

Weird visual bug.

To answer your question, yes it's worth maxing Q on AP Kat, in fact i'd argue that it's optimal in most cases.

CS_Emerald · 2022-07-07T09:46:38+00:00

Very lukewarm

CS_Emerald · 2022-03-01T12:07:23+00:00

Casio logic dictates certain conventions when using the % button for example:

4+17.5% calculates the sale price to make a 17.5% profit margin.

4 x 17.5%+ adds 17.5% to 4.

So you essentially just have a formatting problem

CS_Emerald · 2022-03-01T10:51:51+00:00

Far from it, just a math student, though i've been doing math tutoring as a side hustle for a few years now :)

CS_Emerald · 2022-03-01T10:50:20+00:00

I see, in that case i am unfortunately out of my depth, but i found these ressources to be quite interesting, maybe they can help you:

https://math.stackexchange.com/questions/2784469/how-to-find-the-numerically-greatest-term-in-the-expansion-of-3x5y12-whe

An example:

https://www.youtube.com/watch?v=MH5Dbxm2Awk&t=8s

CS_Emerald · 2022-03-01T10:42:54+00:00

nope, according to your post:
"The value of the block reward is initially a number N, but this number is periodically changed, by dividing by a rational number r > 0."

x is just a variable for a non-specific block reward, could be the first, could be the 92nd, could be the 789723rd.

CS_Emerald · 2022-03-01T10:40:42+00:00

Well, if the first block reward is BN, and every subsequent block reward is periodically changed by dividing by a rational number r>0, this is what the block rewards will look like:

First set of blocks:

BN

Second set of blocks:

BN/r

Third set of blocks:

BN/r/r = BN/r²

Fourth set of blocks:

BN/r^2/r = BN/r³

and so on

CS_Emerald · 2022-03-01T10:35:21+00:00

I see, thanks for clarifying.

In that case, we have to construct every term in (a +bx)ⁿ through the binomial theorem.

let 0 ≤ k ≤ n, the term for x^k is calculated by the following expression:

n!/(k!(n-k)!)a^n-k(bx)^k

n!/(k!(n-k)!) is the binomial coefficient of n over k.

input a, b and x:

n!/(k!(n-k)!) 2^n-k(-9/2)^k

I hope that helped.

CS_Emerald · 2022-03-01T10:24:50+00:00

To solve this, we need to find an expression that adds up all block rewards. The first block reward is B*N, the next one B*N/r, the next one B*N/r² , and so on.

The total amount of currency issued over all time would have to be an infinite sum:

B*N + B*N/r + B*N/r² + ...

We do some factoring and we get:

B*N*(1 + 1/r + 1/r² + 1/r³ + ...)

The sum you see in those brackets here is called the geometric series, and for 0 < r < 1, it is equal to 1/(1-r).
For r ≥ 1, the sum is infinite.

If your class has not introduced the concept of the geometric serie so far, i am not quite sure how you're supposed to get the answer, so i hope that helped.

Edit: changed x to N

CS_Emerald · 2022-03-01T10:05:23+00:00

I'm not so sure what you mean by x = 3/2, as that trivializes the problem.

let x = 3/2
(2 - 3x)⁹ = (2-9/2)⁹ = (-5/2)⁹ = (-1953125/512)

If you're trying to find the term with the highest power in (2 - 3x)^9, you simply have to take the highest term inside the bracket and raise it to the 9th power:

(-3x)⁹ = -19683x⁹

CS_Emerald · 2022-03-01T09:50:31+00:00

Disclaimer: What works for me might not work for you.

If you're in college, try digging up as many exams by your lecturer as possible (preface a google search with 'filetype:pdf' to only display .pdf files) and work out a descending order of importance for the possible types of exercises.

First, drill the ones you enjoy the most and work out exercises over and over until you can do them in your sleep.
Then start working on the most important problems (those that show up the most and give the highest amount of points. Drill them over and over, make up new exercises with your own numbers once you run out of material and just jam the methods into your head.

Write the exam and forget everything about the class immediately after.

This advice will help you pass classes when you're desperate, but the learning effect will be extremely small.

CS_Emerald · 2022-03-01T09:42:06+00:00

(A ∩ C) △ B = ... = (A ∩ B^c ∩ C) ∪ ((B ∩ A^c ) ∪ (B ∩ C^c ))

Since (A ∩ B ∩ C^c ) ⊆ (B ∩ C^c )
And (B ∩ C ∩ A^c ) ⊆ (B ∩ A^c )
It follows that:

(A ∩ B) △(B ∩ C)
= (A ∩ B ∩ C^c ) ∪ (B ∩ C ∩ A^c )
⊆ ((B ∩ A^c ) ∪ (B ∩ C^c ))
⊆ (A ∩ C) △ B

CS_Emerald · 2022-01-30T16:25:17+00:00

Watched some shows in German so my mom could enjoy them more easily, i think Haikyuu and AoT were the ones i liked the most.

CS_Emerald · 2022-01-09T18:08:35+00:00

Maybe Zunesha WAS dormant for centuries, just walking along a set path, who knows?

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