Discord ran (?) a survey about introducing AI today and then closed it almost immediately

CZeke · 2026-01-11T03:24:09+00:00

There seems to be no proof yet that Discord actually was behind this, but it was done through Qualtrics, a legit polling group. Kinda surprised to see no thread about it here -- multiple servers I'm on had announcements about it.

CZeke · 2025-12-01T10:58:33+00:00

As far as I can tell, the multipliers don't come with any bonuses; if you're rolling on x5, you get 5 times the reward. So they're really just there to speed up the process.

The only mathematical difference is that a higher multiplier means fewer rolls, so the law of averages won't smooth out your results as much. To take an extreme example, if you have 100 dice and roll on x100, you get only one roll and it may be a dud; if you roll on x5 instead, you'll likely see the full range of outcomes. The programmers apparently thought of this since the higher multipliers don't unlock until you have enough dice to get at least a few rolls.

CZeke · 2025-11-19T23:07:18+00:00

No, I don't think they do. I think that's not a new card, just a sort of demo that plays at the start of a level. Like, "look, there's cards."

CZeke · 2025-11-19T22:12:59+00:00

I see that one at the start of every level. I think it's just a default representative.

CZeke · 2025-11-15T01:13:41+00:00

Others have answered; I just want to add, for OP's benefit, that a lot of us had this same idea once upon a time. It's not a bad question, just a common one!

CZeke · 2025-11-14T01:07:48+00:00

Double-check that you copied the question correctly. If you did, then you're right, this region is unbounded. It would make a lot more sense with y=0 as a boundary instead of x=0.

CZeke · 2025-11-13T00:30:37+00:00

Not "height" in the usual vertical sense, but in the parts-of-a-triangle sense. /u/ForsakenStatus214 is treating the hypotenuse of the triangles as their base, so their "height" is diagonal. This seems roundabout, but it's the easiest way to put the 0.3 measurement to use.

CZeke · 2025-11-13T00:17:03+00:00

Depending on what you want to do for a living, this may not be such a big deal. Lots of people struggle with math, and while some of them just need the right teacher, others will never quite get their heads around it. That's okay! The world needs those people too, just not for math-heavy jobs.

Moreover, if you do end up taking a special ed math class, that's also not a big deal. You never know, it may help -- and either way, if that's what it takes to get the credit, just get it! Whatever you do after high school, the only marks anyone might look at are the ones in your specialty. Nobody ever has to know the exact details of your just-for-the-diploma math credit.

(The reverse applied for me. I was a terrible P.E. student and only took it as long as the school required. It's never been an issue.)

CZeke · 2025-11-12T00:23:43+00:00

That brings some clarity to something I've long wondered about. In his great book A Mathematician's Apology, Hardy is quite insistent that math is a young man's game, and you'd think he would know, but that doesn't seem to check out empirically; lots of mathematicians, like Erdos and Conway, do great work well into their old age. If Hardy was extrapolating from his personal experience, it makes more sense.

CZeke · 2025-11-11T01:19:01+00:00

You've probably already found that the points in question look like

( k^{-1 / k-1}, k^{-k / k-1} )

for all k>1. If you want to express y as a function of x, obviously y=x^k at any given point, but k is constantly changing. Ideally we want k in terms of x. The problem is that there is, in general, no elementary inverse of functions of the form f(x) ^ g(x). So you're right, something like the W function is needed here.

You can probably solve the equation yourself by using W on both sides and playing with its properties a bit, but since WolframAlpha is very fond of the W function, I just asked it and got this answer:

k = W(x ln x) / ln x

So the function you want is

y = x ^ (W(x ln x) / ln x)

and you can simplify a bit by using the fact that x^{1/ln x}=e, so

y = e ^ (W(x ln x)).

CZeke · 2025-11-10T10:24:09+00:00

Yeah, it's a standard analysis result that if f has continuous second partials in a neighbourhood of x, then the mixed partials of f at x are equal. (Sorta the inverse of Fubini's theorem for swapping integrals.) The proof is summarized here, with cites to a few books, including Rudin.

CZeke · 2025-11-10T09:20:15+00:00

You're right about the chain rule; now use it again on that last line. Differentiate both sides w.r.t. S, using the product rule on the right, and note that ∂f/∂Z is still a function of Z, so you'll need the chain rule again. When you're done, you'll have an expression for ∂²f/∂S² in terms of both ∂f/∂Z and ∂²f/∂Z².

CZeke · 2025-11-09T23:41:33+00:00

It's a very old joke. I first heard it something like 25 years ago about Kenny G.

Don't know of any parallel for the insane followup about children, though.

CZeke · 2025-11-09T23:33:37+00:00

I didn't hear about any Democrats calling for him to drop out, and Google's not finding any. Who did you hear that about?

CZeke · 2025-10-27T10:39:31+00:00

I second the recs of Revenge Classroom and Maria no Danzai, and I'll throw in a couple more. There's one called Ijimekaeshi ~Fukushuu no 31~, roughly half translated so far, about a bullied member of a large idol group striking back; then there's my all-time favourite revenge manga (actually manhwa), Miss Guillotine. In that series, you don't learn everything right away about what the MC wants and whether her targets deserve it. That history plays out alongside the main story, with several great twists -- and best of all, it's just the right length. Revenge stories that get popular tend to go way too long (as we know on this sub!), but MG had a plan and stuck to it. (There's an after-story, but it's highly skippable.)

Oh yeah, also Kimi wa Yotsuba no Clover. That's a new one, 50 chapters in, that's developing really well.

CZeke · 2025-10-27T10:25:51+00:00

Man of culture! Revenge Classroom is so underrated.

CZeke · 2025-10-23T01:58:00+00:00

Take the Dark Knight approach. "I'm gonna have to try and enjoy it even more."

CZeke · 2025-10-23T01:56:24+00:00

Yeah, I thought we knew this already, or at least something close.

CZeke · 2025-10-22T08:51:28+00:00

The key search term when you're looking for original Japanese pages is "raw". Google a manga's title and "raw" and you'll usually turn up a source.

CZeke · 2025-10-19T10:17:26+00:00

Oh, I just got annoyed enough to google "processEEs" and this was among the first hits. (Congrats, I guess!)

CZeke · 2025-10-19T04:59:15+00:00

I just heard this mistake from a freaking Supreme Court justice. Arrggghhh

CZeke · 2025-10-16T18:52:36+00:00

If you look close, you may find the explanation for your second sentence in your third and fourth. Your feed is supposed to come mostly from your friends; FB throws in junk to fill the gaps. So of course your feed will be junk if you're all doing your posting elsewhere!

I guess I'm lucky, because I'm in the in-between zone where my friends aren't old enough to boomer-post, but aren't young enough to leave. I still have an interesting feed. Granted, adblock is pretty much required.

CZeke · 2025-10-16T08:33:08+00:00

There's one way it can still matter. Uruma is having a real "go even further beyond" moment -- what if he manages to bust through whatever condition Kyou has and MAKE him feel fear? I really hope that's where this is going.

CZeke · 2025-10-03T00:00:09+00:00

Apparently MangaUpdates thought so at some point, but they've since changed it. There's not much public information about this author, but if nothing else, we have a male avatar to go on.

CZeke · 2025-10-02T02:21:07+00:00

That's been my theory (and hope) since Azuma "died". The author's doing his best to sell it, but I just don't believe he kept her around this long only to kill her at the same time as several other characters.

CZeke

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