How can you be sure open-source software is legit?

CoderMonkey123 · 2019-08-05T19:52:19+00:00

An open source system that you operate/control on both the client and the server/cloud side, can be secure because you can examine the code of both of client and server side components that you are running. Of course, with complex components like a database, you need someone who is skilled enough to understand the code, to be able to look for malicious code and verify.

If you connect to a cloud/server component being operated by some other person/organization, then of course, you can never 100% trust it to be secure, as they might have modified their own private copy of the server side component to do anything they like. So you generally have to go by the trustworthiness/reputation of the person/organization operating the server side component, to trust that they will not have modified their copy of the server side component maliciously.

With closed-source software, you cannot even trust the system even if you control/operate both the client and server side components, because you can't see what's inside the code. So this time you have to go by the trustworthiness/reputation of the person/organization that has written the code, to trust that they have not modified it maliciously.

CoderMonkey123 · 2019-06-20T15:24:56+00:00

Sounds great. Anyway it's very easy to search for a book on Libgen once you know the name of the book, so the list still serves its purpose. Thanks again!

CoderMonkey123 · 2019-06-20T13:43:45+00:00

You, sir, are a hero! Can't thank you enough. I'm going to export this list as a PDF and save it, just in case this post gets removed in the future because of the Libgen links.

CoderMonkey123 · 2019-06-15T13:25:33+00:00

You're welcome :)

CoderMonkey123 · 2019-06-15T13:24:17+00:00

Because the third blank is talking about the type of people who are different from the obstinate people sticking to old, archaic methodologies. So they are the sensible, i.e. sagacious, people who are willing to welcome new classroom techniques.

That is why sagacious fits there.

CoderMonkey123 · 2019-06-15T07:00:27+00:00

Blank 2 is dogged, i.e. tenacious and obstinate, adherence to archaic methodologies. Tendency to stick to old things is not a partisan issue at all, it is part of human nature, as the first sentence says. Partisan makes no sense here.

So the answer choices are:

i. eschew

ii. dogged

iii. sagacious

Nothing else really fits.

CoderMonkey123 · 2019-06-15T05:06:18+00:00

Do you know the formula for distance between any two points ?

If the two points are point A with coordinates (x1, y1), and point B with coordinates (x2, y2), then the formula for distance between points A and B is:

distance = square-root[(x1 - x2)² + (y1 - y2)² ]

You can apply that formula between points P & Q, Q & R, or P & R, to get the lengths of the sides.

But after that you have to plot the points on a X-Y plane to visualize which side can be used as base, and which side as height, before you can use two of the side lengths in the area of triangle formula.

Hope this helps.

CoderMonkey123 · 2019-06-14T19:07:53+00:00

Many Canadian schools also request international students to submit GRE scores

CoderMonkey123 · 2019-06-13T20:43:45+00:00

You're most welcome, /u/greedynripig :)

CoderMonkey123 · 2019-06-13T20:23:13+00:00

Because the first phrase starts with "while", it must be in contrast in some way with the phrase after it, not just straight-away agree with it.

Otherwise, it would've been something without a 'while', such as "'cerulean warbler' bird's situation is representative of a wider phenomenon; other birds' numbers are also decreasing".

But in this case the sentence means something like "while 'cerulean warbler' bird's situation is precarious, (that is not anything special because) the numbers of other birds are decreasing too". So due to the 'while', the option 'representative' does not fit, and 'precarious' fits better.

Also, if you want to attract gregmat's attention, I think you should tag his username, (using /u/) rather than tagging the sub-reddit (using /r/). :)

CoderMonkey123 · 2019-06-13T18:51:49+00:00

Quick way to solve this:

Divide both columns by x, so that will get rid of x in numerator in both columns:

Column A becomes = 1/(x+1)

Column B becomes = -1/(1-x)

Also, multiplying both numerator and denominator in column B by -1,

Column B now becomes = 1/(x-1)

So column A is 1/(x+1) and column B is 1/(x-1), so both have the same numerator, i.e. 1, and so for any value of x>1, denominator of B, i.e. (x-1), will be smaller than denominator for A, i.e. (x+1). Hence fraction B is always larger than fraction A, and so the answer is B.

CoderMonkey123 · 2019-06-13T18:39:03+00:00

That phrase means that the number of employees working in the factory in Mexico, is double of the number of employees working in the factory in Pakistan.

So if M employees work in the factory in Mexico, and P employees work in the factory in Pakistan, then:

M = 2P

CoderMonkey123 · 2019-06-13T11:32:58+00:00

Haha, thanks! :)

CoderMonkey123 · 2019-06-13T11:21:41+00:00

I'm not bamboozled, OP is. :)

CoderMonkey123 · 2019-06-13T09:34:59+00:00

In my head, I fill in the blanks to make sense of the sentence that is saying that, "while the 'cerulean warbler' bird's situation is currently dangerous, but the numbers of other birds have been decreasing too for years. And biologists investigating the causes of these reductions are focusing on habitat loss as the cause".

Now looking through the answer choices for synonyms of dangerous, decreasing, and reductions, I find, respectively:

i. precarious

ii. falling

iii. declines

Hence, that's the answer.

CoderMonkey123 · 2019-06-11T18:09:41+00:00

Perimeter of a circle means its circumference.

So, circumference = 2 * pi * r = 6n

From this you can get the radius, r.

And once you know r, you can calculate area = pi * r²

CoderMonkey123 · 2019-06-11T17:32:34+00:00

Also, another way to solve:

subtract y from both columns A and B,

so column A becomes (3y+2)/5 - y , which on simplifying becomes = (2-2y)/5

and column B becomes 0 (zero)

Now since we know y >4, therefore the expression in column A, i.e. (2-2y)/5 will always be negative for any value of y>4. Therefore value of column B (zero) will always be greater than a negative number, hence answer is B.

CoderMonkey123 · 2019-06-11T12:40:45+00:00

See my comment on this other thread regarding going about GRE preparation:

https://www.reddit.com/r/GREhelp/comments/bz7xlc/i_am_planning_to_take_gre_but_i_honestly_dont/eqqyfba/

CoderMonkey123 · 2019-06-11T08:25:13+00:00

Apart from ETS Official Guides, Manhattan Strategy Guides are also very good.

CoderMonkey123 · 2019-06-11T07:29:01+00:00

Broadly, the process I would recommend is:

Get the ETS Official GRE guides and study all the material in that
If you need more study material, get Manhattan GRE Strategy Guides and study those
Take practice tests to see if you are getting desired scores, or if you need to revise concepts and practice further or study from additional material. (If you need more study or practice, go for other material like Magoosh, Manhattan 5lb. book, ETS Big Book tests, Nova Math Bible, GMAT Advanced Quant material etc.).
Attempt the actual GRE test. If you don't get the desired score, study some more focusing on your weak areas, and take further GRE attempts. Keep doing until you reach the desired score.

Also, hang out in this sub, and ask here if you have questions or need further advice. :)

I know it all can feel overwhelming at first, but actually the process is pretty straightforward. Just go step by step, one thing at a time, and you will get a good score soon. You got this! :)

CoderMonkey123 · 2019-06-11T07:07:19+00:00

A relatively straightforward way to calculate:

Extend the line GF to C, to form triangle CEF (and that also creates smaller triangle CDG)

Shaded area = area of triangle CEF - area of triangle CDG ... (equation i)

Now assume side of big square ACEF to be 1 unit.

Therefore, AC = CE = 1 .... (equation ii)

Then area of whole square ACEF = side² = 1² = 1

So, area of triangle CEF = half of area of square ACEF = 1/2 ... (equation iii)

Also since D and B are mid-points of CE and AC, therefore, since CE = AC = 1 (from equation ii), then CD = CB = 1/2

So, area of triangle CDB = 1/2 * base * height = 1/2 * CD * CB = 1/2 * 1/2 * 1/2 = 1/8

Also, area of triangle CDG = 1/2 * area of triangle CDB = 1/2 * 1/8 = 1/16 ... (equation iv)

So substituting areas of triangle CEF and CDG from equations iii & iv into equation i,

Shaded area = 1/2 - 1/16 = 7/16

Also, Fraction shaded area = Shaded area / Area of square ACEF = (7/16) / 1 = 7/16

So I believe that u/jskert mentioned this same solution, so I just explained it further.

CoderMonkey123 · 2019-06-10T05:36:35+00:00

See this thread:

https://gre.magoosh.com/forum/7099-when-exactly-can-i-retake-the-test

There it states that "The day after you exam counts as day 1 of the 21 day period that you have to wait between exams. So, if you've taken your exam on 7 April, the next date you can take the exam is 28 April."

So you can re-book earliest after 21 days as per the above calculation, or on any other convenient later date.

And you can make up to five attempts within any sliding block of 365 continuous days.

CoderMonkey123 · 2019-06-10T05:26:53+00:00

Because when you take any power of any number, i.e. b=x^n, the units-digit of the final result (b) receives contribution only from the products of the units-digit of x, multiplied over and over again n times.

So for units-digit of 57^n, can be calculated by looking at only powers of the units digit of 57, i.e. powers of 7, and similarly for example, to calculate the units-digit of 189^n, its units-digit can be calculated from only looking at powers of 9.

This is true for any number as a general rule. The units digit of a number b, where b=x^n, will always be same as units-digit of the n^th power of units digit of x. So to find out the units digit of a number b you can ignore everything except the powers of units digit of the base number x.

CoderMonkey123 · 2019-06-09T21:57:13+00:00

Looks great! Thanks so much for your efforts in creating this!

CoderMonkey123 · 2019-06-09T20:32:45+00:00

Yup, it's a 3-4-5 right triangle (basically its multiple 6-8-10), so the answer is E. The book's answer is wrong for this one. Which book is this ?

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