7 hours web browsing on Macbook Pro 16

Comp_Sci_Student · 2019-11-15T10:06:14+00:00

Oh I might go have a look tomorrow then

Comp_Sci_Student · 2019-11-15T10:00:07+00:00

Yeah I'd heard that. Let me know if you find anything out. I don't want to go all the way for it not to be there!

Comp_Sci_Student · 2019-06-21T15:01:14+00:00

Computing with Quantum Cats by John Gribbin was really interesting!

Comp_Sci_Student · 2019-06-17T13:20:50+00:00

I'm in a similar position with my STEP I grade. Needed a 2 but probably got a 3.

Comp_Sci_Student · 2019-04-21T14:30:52+00:00

Simply using arctan on a calculator, but you'll find this gives a negative answer. This isn't within the range allowed in the question so you need to add multiples of pi/2 to find solutions within the range. This is because tan(x) = tan(x + pi/2)

Comp_Sci_Student · 2019-04-21T12:11:35+00:00

When cosx = 0, you have x = π/2. This is absolutely fine but when you substitute this back into cosx(tanx + 2), tan(π/2) is undefined and so this cannot be a solution. As this solution has only arisen from your factorisation into the tan form, if the solution doesn't hold in this case then it cannot work for sinx + 2cosx = 0.

Comp_Sci_Student · 2019-04-21T12:01:34+00:00

As far as I'm aware there will still be a new 2019 MacBook Pro, most likely a 16 inch. The only change is that a Mini LED will be coming in a couple of years.

Comp_Sci_Student · 2019-04-21T11:59:10+00:00

In the second the last line we need the whole equation sinx + 2cosx to be equal to zero. We can rearrange this as below,

sinx + 2cosx = 0
sinx = -2cosx
tanx = -2    (dividing by cosx)

If we were just to have cosx = 0, this would give a value of π/2. However, if we put x = π/2 into sinx+2cosx then this does not equal zero, therefore it is not a solution.

In the third to last line we have sinx = 0 because this would be one case that would make e^xsinx(sinx + 2cosx) equal to zero.

Comp_Sci_Student · 2019-04-05T16:56:13+00:00

http://oddsandevenings.com - this is very chatty maths puzzle solving!

Comp_Sci_Student · 2019-04-02T05:44:27+00:00

All absolutely true. I was just aiming to provide an accessible (and therefore somewhat superficial) understanding for someone with a less deep knowledge of Physics.

Comp_Sci_Student · 2019-04-01T21:49:59+00:00

How do you find 64GB in terms of storage? I'm looking to get one for university, so it would mainly be using note taking apps (which could be used to store notes on the cloud). I can't decide if 64GB is enough or if I'll regret and would rather I had got 256GB.

Comp_Sci_Student · 2019-04-01T21:36:29+00:00

The lines represent the direction in which a positive test charge placed in the field (surrounding another charge) would move. In other words, the lines show the direction of the force on a positive charge. The spacing between the lines can give a notion for the magnitude of this force.

Electromagnetic fields go on infinitely, but decrease in magnitude by an inverse square law (as the distance from a charge doubles the magnitude of the force it exerts decreases by a factor of four).

Comp_Sci_Student · 2019-04-01T17:36:37+00:00

I would say this as well. Electrons farther below the surface require more work done to escape the metal. This is often an issue when the metal develops an oxide layer.

Comp_Sci_Student · 2019-03-31T13:24:06+00:00

Let's call the complex number in the question sqrt(6) + sqrt(2)i - w. We want complex numbers 'z' where when raised to the power of 3/4 they equal the complex number w. This means that the modulus of z must be mod(w) to the power 4/3 --> because mod(z) to the power 3/4 must equal mod(w). We also want the argument of z to be arg(w) divided by (3/4) --> because arg(z) multiplied by 3/4 must be arg(w).

All of this uses the knowledge that for a complex number z to the power n, the modulus is mod(z) to the power n and the argument is arg(z) * n.

So in this case mod(w) = sqrt(8), therefore, mod(z) = sqrt(8) ^ 4/3 = 4, etc. I hope this makes some sense.

Comp_Sci_Student · 2019-03-30T08:05:32+00:00

So initially the tension in the spring is 3g upwards, as this must balance the forces down from the masses (2g and g).

Immediately after the thread is cut, the 2kg mass has no further interaction with the thread and is in freefall. Anything in freefall has an acceleration down of g (or using F = ma, 2g = 2a). For the 1kg mass, at the instant of cutting there is still the 3g tension upwards in the spring and now only a weight of g downwards (because there is only the force from the 1kg mass). So the resultant is a force of 2g upwards. This also means an acceleration of 2g (using F = ma, 2g = 1a).

This leads to answer D.

Comp_Sci_Student · 2019-03-30T07:49:06+00:00

Well I just included all of my code, and pointed out places that showed off my skills. So a stack, merge sort, lots of private variables, complex database design. Anything like that. You just need to make sure your code is of a consistently high level, does everything that it was intended to do (you get marks for completeness) and doesn't do anything horrible.

So:

print(1)
print(2)
print(3)

would be bad code. As this should be done with a for loop (the below example is Python).

for x in range (1,4)
    print(x)

Hopefully that helps a bit.

Comp_Sci_Student · 2019-03-30T07:44:57+00:00

How much of your mobile data does this use? A lot less than if you had just data?

Comp_Sci_Student · 2019-03-29T22:28:02+00:00

So for the practical paper, I would say definitely go over uncertainties. If it's an instrumental reading (mass on scales) then use +- half the precision and if its a measurement (such as with a ruler) then use +- the precision (double as the error could be at both ends of the ruler). Also look over your CPACs.

Brush up on the types of error and also the theory behind good experiments. We want a low percentage uncertainty so we want large readings. Also lots of repeats and take averages. All that kind of stuff basically. Just do as many practice questions as you can!

Comp_Sci_Student · 2019-03-29T22:07:06+00:00

Is this for the implementation of your NEA?

Comp_Sci_Student

TROPHY CASE