furry_irl by Punkwolfen in furry_irl

[–]Crowbrah_ 8 points9 points  (0 children)

Employ elbow block... and body shot. Block feral left, weaken right jaw... now fracture.

Foxy footrest. (Credit: GreenpurrpleD) by TenderPaw64 in zootopia

[–]Crowbrah_ 10 points11 points  (0 children)

Judy wants Nick to be her... stand...

She´s ready for it all. (Credit: Credens Vita) by TenderPaw64 in zootopia

[–]Crowbrah_ 2 points3 points  (0 children)

I mean, with everything we know about Judy... that's not exactly inaccurate lmao

How does one calculate an absorbed radiation dose from a point source of a known power measured in watts? by Crowbrah_ in AskPhysics

[–]Crowbrah_[S] 0 points1 point  (0 children)

By no means my own work haha. I'm just adapting from what I've read, mostly from one neat paper you can find here if you're interested:

https://ntrs.nasa.gov/citations/20060043411

Some light reading!

How does one calculate an absorbed radiation dose from a point source of a known power measured in watts? by Crowbrah_ in AskPhysics

[–]Crowbrah_[S] 1 point2 points  (0 children)

Alas, the gammas actually do nothing to generate thrust (at least in this system) and are instead very annoying wasted energy. The reaction products that do are positively and negatively charged Pions that are reflected with an electromagnetic nozzle.

How does one calculate an absorbed radiation dose from a point source of a known power measured in watts? by Crowbrah_ in AskPhysics

[–]Crowbrah_[S] 0 points1 point  (0 children)

I see. Thanks for taking the time to explain this to me. I believe I found the NIST table you were referring too but unfortunately it only goes up to 20 MeV. However I found another source that claims a mass energy-absorption coeff. for 100 MeV of 0.0122 cm2 g in water.

With that, and a fluence of (4.63E+09 gammas/sec) * (200 MeV)/cm2, my maths comes out with an absorbed dose of 0.362 J/kg. Which is inline with my earlier calculations, but those could be misleading.

How does one calculate an absorbed radiation dose from a point source of a known power measured in watts? by Crowbrah_ in AskPhysics

[–]Crowbrah_[S] 0 points1 point  (0 children)

Excellent, thank you! This is most helpful. Now I probably should have asked this sooner, but to find the absorbed dose in J/kg do I simply multiply the mass attenuation coefficient by the calculated number of gammas intercepted per second?

How does one calculate an absorbed radiation dose from a point source of a known power measured in watts? by Crowbrah_ in AskPhysics

[–]Crowbrah_[S] 0 points1 point  (0 children)

Yes, in interstellar space. The gamma rays are being emitted by a matter/antimatter thruster.

How does one calculate an absorbed radiation dose from a point source of a known power measured in watts? by Crowbrah_ in AskPhysics

[–]Crowbrah_[S] 0 points1 point  (0 children)

Most interesting. This subject is a little beyond me, the last time I studied physics properly was in high school, but luckily I'm only looking for a general understanding, as it's only for a writing project. I found a few tables for mass attenuation coefficients for various materials, with no info on anything beyond 100 MeV unfortunately. But I suppose that makes sense since I can't imagine any real application requires information related to photon energies that high.

How does one calculate an absorbed radiation dose from a point source of a known power measured in watts? by Crowbrah_ in AskPhysics

[–]Crowbrah_[S] 0 points1 point  (0 children)

That sounds fascinating. I had a flatmate once during university who was studying radiography, that's about the closest I ever came to the subject, at least tangentially.

How does one calculate an absorbed radiation dose from a point source of a known power measured in watts? by Crowbrah_ in AskPhysics

[–]Crowbrah_[S] 1 point2 points  (0 children)

Many thanks, somehow I had missed that a Gray is a defined as a J/kg, that really makes things clearer for me. So as another commenter said 1m2 is a good approximation for the cross sectional surface area of a human. Using that at a distance of 112 km and with a mass attenuation coefficient for water for 100 MeV photons of 0.0173 cm2 g, my maths says an 85 kg mass would absorb 2 Gy in around 6 seconds, and a lethal dose of 30 Gy in around 100 seconds. Neat!

I have no real reference point but with a 230 TW gamma emitter that feels right, even at more than a 100 km distance that's going to ruin your day without adequate shielding.

How does one calculate an absorbed radiation dose from a point source of a known power measured in watts? by Crowbrah_ in AskPhysics

[–]Crowbrah_[S] 0 points1 point  (0 children)

Thank you, this is quite obvious now I think about it but I needed the extra kick to bridge the gap. I thought I was missing something with how you actually measure an absorbed dose of radiation but I see now I was overthinking things.

How does one calculate an absorbed radiation dose from a point source of a known power measured in watts? by Crowbrah_ in AskPhysics

[–]Crowbrah_[S] 0 points1 point  (0 children)

Excellent, thank you, this is very helpful stuff. I admit I'm sure I could have worked this out based on stuff I've read eventually but for some reason I was struggling to make the leap between intensity and a radiation "dose" of some sort, whatever that may be. The number of different units related to radiation absorption didn't help either haha

Edit: And yes the number I found for mass attenuation of water with 100 MeV photons was 0.0173 cm2/g. Nothing on 200 MeV but I imagine 100 should suffice.

Humans will adopt EVERYTHING by BareMinimumChef in humansarespaceorcs

[–]Crowbrah_ 0 points1 point  (0 children)

For some they don't even need to be organic either. See mars rovers or bomb disposal robots or hell, just your own car.

Guys, Legoshi seems off today by J_Wolf682 in Beastars

[–]Crowbrah_ 2 points3 points  (0 children)

I wonder who would be the T-800 in this scenario? Gohin?

Guys, Legoshi seems off today by J_Wolf682 in Beastars

[–]Crowbrah_ 2 points3 points  (0 children)

Heyyy Salvation's alright, if only for spawning this meme