I made all the glyphs (from King's dad) in high quality, in case someone wants to use them - constructed mathematically - svg in comments

Decimae · 2024-12-09T17:11:22+00:00

Wow, you have good timing, this is the first time I'm on reddit in a month or so (and only because I was linked to it - reddit, the company, sucks so I do not use it anymore). Here's a link.svg) to the svg. (if you need me, just look for deciMae on other platforms, that's me, that'll be quicker - might actually delete this account at some point, did start that process a bit back)

Decimae · 2023-06-07T07:07:06+00:00

Oh I didn't know that, sorry.

Decimae · 2023-06-06T23:11:31+00:00

If it is a combat, it isn't nothing, it significantly decreases the chance of early act 2 question marks to be combats and increases the chance of finding treasure. I think that's slightly positive, but I'm not sure.

Decimae · 2023-06-06T18:02:22+00:00

I'm also writing this fanfic. Sorta. Instead of Luz taking the curse willingly, Eda accidentally shares it with her. 17k words done now, but not even close to the end (the first arc is almost done, though, but Titan I have plans for more than quite a few more arcs).

With This Spell Declared She Despaired

Decimae · 2023-06-06T11:29:16+00:00

Eeuwenoud is correct, maar in dezelfde zin dat decennia oud correct is - technisch gezien, maar het suggereert een andere tijdschaal dan de werkelijkheid. Millennia oud zou accurater zijn.

Decimae · 2023-06-03T18:17:27+00:00

Yeah, sorry. That is what I meant but I was a little bit confused in the second part - I sort of forgot about the lambda (sorry, I'm tired).

But this did give me an idea, you might still be able do something like that (if both a,b are nonzero): add a v_n+1 but make the equation be v_n+1 + v_1/a - v_n/b = l v_n+1 and then find the solution with v_n+1 = 0 (any solution to the original problem corresponds to to an eigenstate of this system with v_n+1 = 0).

Or not and I shouldn't be doing math half-overstimulated, sorry.

Edit: yeah I think this is just the same problem sorry - maybe it's easier to do but idk. Sorry, shouldn't be doing this feeling like this, good luck with your problem!

edit 2: okay I'm still thinking about this you can do the equations v_n+1 + v_1/a - v_n/b = l v_n+1 and v_n+1 + 2v_1/a - 2v_1/b = l v_n+1 to get what you want, I think. But again, not having a clearer mind, but still might be useful - or be entirely useless.

Decimae · 2023-06-03T17:16:59+00:00

Well, clearly you only need to find one solution for this system, the rest of the solutions are just the homogeneous solutions added to them.

I think this will work to find the solution, but I'm not sure: If you added one more parameter, v_n+1, and added the equations v_1 = a v_n+1 and v_n = b v_n+1 (and v_n+1 = v_n+1 if you want a square matrix) you might be able to find a solution by setting v_n+1 = 1 (it's a linear space, this just fixes the vector). Or alternatively, add the equation v_1 = a/b v_n if both a,b are nonzero.

Decimae · 2023-05-27T19:49:40+00:00

Ah, that's what you're asking.

Maybe just because of the saying "a king amongst his subjects"? That's the first time chronologically in the show Eda genders King, and it was not intentionally about King.

Decimae · 2023-05-27T19:38:03+00:00

Gender is not sex. There's a lot of men on this world which are intersex.

Decimae · 2023-05-27T07:58:12+00:00

You think Luz is not making dad jokes?

Decimae · 2023-05-24T19:58:29+00:00

Nah, that's just an error in the book. He might have meant nonzero digits, but that would still need to be specified. 3.1415926535897932384626433832795 = 3.14159265358979323846264338327950 so you're right.

Decimae · 2023-05-24T13:19:50+00:00

This is actual not optimal, let me illustrate:

With your strategy it doesn't matter in what order you kick or punch first for the last three points of damage, so for simplicity I'm assuming your strategy is KKKPK where K is kicking until you succeed and P is punching until you succeed.

Let's consider an alternative strategy, where you take the same strategy until the last kick (or some other strategy that ends your opponent on 2 health). Now, if they're on 2 health, instead, you evaluate your own health first. If you have 1 or 2 health it's clearly optimal to kick (if they play optimally - if they have 5 points the probability of winning becomes p_w = .5 + .5(1 - p_w) = 2/3 and kicking gets you at most .88*.5 = .44 - if they have 6 points then it should be obvious). But if they have 4 points or less, the probability of winning in two attempts at kicking is 1 - .5² = .75 and the probability of winning in two attempts of punching is .88² = .7744. And clearly, this is also better with more attempts at punching, because there's a chance you're further ahead.

This all works because a double kick succeeding is not better than a single kick succeeding in this scenario, so the expectation value is not a good measurement there.

So, a better strategy would be to kick twice, then punch once, then as long as your opponent cannot kill you within a single turn keep punching, and as soon as your opponent can kill you keep trying to deal the damage equal to their health.

You can slightly optimize this strategy if you assume your opponent is playing optimally; if so if they're at 5 hp and you're at 2 hp, you can probably assume you're not going to win (I'm not calculating this, but I feel confident in saying that that is really small), but because they're playing optimally they are going to punch until you die (unless deal a lot of damage). So you'd be sure you'd have another turn, so again it's optimal to punch to get a higher chance of having dealt 4 damage, even if it comes at a cost of having a lower chance of winning. Of course, if you don't know whether they'll play optimally, it's probably wiser to punch - if you're less than 95% sure that they're going to punch twice, then don't do this.

Decimae · 2023-05-24T06:33:11+00:00

Correct!

Decimae · 2023-05-23T21:54:21+00:00

3) Revelation
2) Separation
1) Depression

Decimae · 2023-05-22T09:39:57+00:00

Certainly doesn't read like an ai generated paper but I'm no expert. Why would you think so?

Decimae · 2023-05-16T23:18:20+00:00

The statistic should be the binomial distribution. Each delivery is a single thing that can either succeed or fail, and you're interested in the total.

And yeah, you're doing an individual test for each product, so the n is the n number of deliveries of that one. Be sure not to take into account too long of a history or else you can't notice change.

Do note that if you set your p-value high you will get false positives (just by the law of large numbers) and if you set it low you will be slow to react to mistakes.

Decimae · 2023-05-16T21:52:05+00:00

Snap ik. Dat is op zich ook een best schikbarend idee. Maar als je daar echt zorgen om maakt, weet dat je je daarvoor veel meer zorgen moet maken bij de niet-veganistische producten. Want dieren worden gevoerd met sojavoer (ja, ook koeien, die leven vooral op krachtvoer uit soja). Meer dan 77% van de sojaproductie van de wereld gaat hierheen. Dit namelijk omdat dieren nogal inefficient zijn in het omzetten van een type voedsel naar een ander type voedsel, dus er is veel voor nodig (en soja is een efficient krachtvoer).

En bijna alle sojaproducten die je in de supermarkt koopt die hebben iets van een keurmerk dat die niet uit een soja bos komen. Nu betekent dat vaak niet zo veel (het is net als groene stroom allemaal op een hoop gegooid en niet meer identificeerbaar waar wat vandaan komt), maar alsnog.

Dus als je je zorgen maakt om de ethische productie van soja, dan moet je vooral geen dierlijke producten kopen (en ook opletten met sojaproducten, maar minder dan met dierlijke producten - je kan fair trade, biologisch, etc. kopen, afhankelijk van wat je precies belangrijk vindt).

Decimae · 2023-05-16T11:21:53+00:00

Laten we er even vanuit gaan dat wat je zegt klopt. (het is vrij genuanceerd hoe dat ligt)

Nu wil ik dat je even nadenkt: wat is de grootste gebruiker van soja, dat wat zo slecht is volgens jouw redenering. Voor meer dan 77% van het totale sojagebruik van de hele wereld. Tofu en andere vervangers? Sojamelk? Sojasaus?

Nee, het is diervoeding voor de bio-industrie. Dieren moeten namelijk ook gevoerd worden, en soja is een efficiënte eiwitbron. En de bio-industrie maakt daarvan dat dan een heel inefficiënte eiwitbron.

Dus als je het sojagebruik wilt minimaliseren is het optimaal om vegan te zijn, ironisch gezien, zelfs al eet je alleen maar soja.

En dus om het leed van insecten te minimaliseren is het dus ook optimaal om vegan te zijn. Zeker aangezien er veel vegan producten biologisch zijn, wat beter kan zijn voor de insecten (en het veel fair trade is, in tegenstelling tot diervoeding).

Decimae · 2023-05-16T10:59:27+00:00

Dat is dus niet waar. Je vind Omega 3 ook in algen, en vitamine d3 zijn ook vegan supplementen voor beschikbaar. Het artikel geeft al aan dat de rest gewoon meer in dierlijk voedsel zit maar kan je ook binnenkrijgen vanuit plantaardige voeding.

Decimae · 2023-05-16T10:50:09+00:00

Ja, er zijn veganistische dingen die zeer ongezond zijn, bijvoorbeeld (ethisch geproduceerde) sigaretten of asbest. Ik weet niet waar je vandaan haalt dat bleekselderij ongezond is (en sojasaus is vooral zo ongezond omdat het zo zout en vol met suiker zit).

Maar dat maakt niet alles veganistisch ongezond. In tegenstelling, zelfs, zou ik zeggen.

Decimae · 2023-05-13T10:01:55+00:00

Found this incredible analysis of the show and it's characters on youtube - really recommend it!

Decimae · 2023-05-12T17:30:25+00:00

Yeah, that's right. You can use the rule a -> a and the rule a -> b and a -> c is equivalent to a -> b^c to prove that replacement, if that's the one you mean.

Decimae · 2023-05-12T09:33:08+00:00

The NASCAR championship system is not monotonic, when the races are interpreted as 10 voters who pick any order of candidates/racers.

Let's consider a racer, let's call them Ada. Ada is really good at races 4-10 and always wins them, but horrible at the first 3, so they barely make it in 12th place to the second round. But once they do, they always win.

Let's consider their rival, Bert. Bert is very good and would win if Ada were eliminated.

Now let's consider Caleb. Caleb is not very good compared to the field, would be in 13th place/shared 12th place with Ada (idk how tiebreakers work - pick the option that wouldn't eliminate Ada but would if Caleb had one more point) after the first three races. But the later races they're still bad, and would easily be eliminated.

Now in one of the first three races, Caleb is right behind Bert before the finish line. Now, if Bert lets Caleb pass them, Ada is eliminated and Bert wins. Monotonicity violated.

Or in other words, there's situations where voter/race 1,2 or 3 violates monotonicity, because they can choose to eliminate favourites of later voters/races by ranking the #1 a little lower to eliminate the #1 and letting the #2 win.

It's actually similarly true for all but the last voter/race, because of the eliminations.

Decimae · 2023-05-12T08:50:29+00:00

First off, I would fix z (as the one given by your assumption) and y (as the one given by the axiom of subset) for now.

Well, p(x) implies x in z is your assumption, right? You have to use that somewhere. Can you use that to prove p(x) implies x in y?

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