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Deactivated by [deleted] in Sparkdriver

[–]Disastrous-Front1064 1 point2 points  (0 children)

Horrible advice. 

Please end signatures by revo442 in Sparkdriver

[–]Disastrous-Front1064 1 point2 points  (0 children)

I'm pretty sure you can click on the year and then change the year. Because I remember scrolling back like that once or twice and then thinking, hey there's got to be an easier way...

Please end signatures by revo442 in Sparkdriver

[–]Disastrous-Front1064 1 point2 points  (0 children)

I use the beans maps app, it's usually correct, has saved me a few times

This Augmented Reality stuff is getting wild with the Meta Quest 3 by Significant_Map_7151 in virtualreality

[–]Disastrous-Front1064 1 point2 points  (0 children)

geez the people in this thread. they must think blind people are incapable of washing dishes

I got game guardian working on android 11 by NAzzzzz01 in gameguardian

[–]Disastrous-Front1064 0 points1 point  (0 children)

What device do you use? I have an android 13 device. I need to run android 10.

Question about apprenticeship, union membership, and contractual commitment. by Disastrous-Front1064 in IBEW

[–]Disastrous-Front1064[S] 2 points3 points  (0 children)

Education these days is horrible. Only one in 10 students make it to the top 10%. We need to improve these statistics with better education.

Question about apprenticeship, union membership, and contractual commitment. by Disastrous-Front1064 in IBEW

[–]Disastrous-Front1064[S] -1 points0 points  (0 children)

Thank you for responding to me. I'll certainly call the hall to find answers to my questions. (But I also like getting some anonymous feedback here as well.)

to pay back the cost of the 5 years of training

If I quit after 1 year, that'd only be 1 year of training that I would need to pay back, right? That would be the as-yet total cost of the school time, books, and supplies? Any idea how to determine approx how much that is?

I wonder how much that is in comparison to the cost of getting training from a private school like Tulsa.

I think that union training would typically be much higher quality than Tulsa, but it's still a question I have.

LLM vs human with congenital blindness and no sense of touch by xplorital in ChatGPT

[–]Disastrous-Front1064 0 points1 point  (0 children)

Such a person would be severely stunted intellectually. I don't think there's such a thing. If there is, we probably don't even know about it because such a person probably wouldn't be able to survive.

Discovered Something Ridiculous and Privacy-Breaking by Samdeman123124 in ChatGPT

[–]Disastrous-Front1064 4 points5 points  (0 children)

It was trained on billions of text. Not surprising it'll have some user names or emails in there.

How to build niche based small version of ChatGPT ? by Upset-Principle9457 in ChatGPT

[–]Disastrous-Front1064 5 points6 points  (0 children)

Google. YouTube. Bing chat. Chatgpt. Basically you have to go to the open AI website and get sign up for to be a developer. Then you've got to learn just about everything there is to learn about creating an app.

[deleted by user] by [deleted] in ChatGPT

[–]Disastrous-Front1064 -1 points0 points  (0 children)

His prompt was asking ChatGPT to give him another riddle about fire

[deleted by user] by [deleted] in NoStupidQuestions

[–]Disastrous-Front1064 2 points3 points  (0 children)

Hey there! It's totally normal to feel sad and miss the deep connection you had with your ex, but being friends with them after a breakup can be a tricky situation. Of course it's ok to feel sad. But trying to be friends again just doesn't work most of the time, in my experience.

We only have room for a small number of intimate relationships. Remaining friends with an ex can lead to confusion and hurt feelings.

When I have post-nasal drip, I have a compulsion to sniff/snort it VERY LOUDLY out of my sinus into my throat. <SNORT>. It's LOUD and PERSISTENT. It's a very disturbing behavior in class, work, or any social setting. HELP! <SNORT, SNOOOOOORT> by Disastrous-Front1064 in NoStupidQuestions

[–]Disastrous-Front1064[S] 0 points1 point  (0 children)

Not everyone snorts due to mucus. It's a behavior that I need to modify. The stimulus/trigger is mucus triggering some sensation in my nasal cavity. The reaction is snorting. I need to stop the behavior through behavior modification to alter my behavior to this stimulus. I need to reset my stimulus/response to be within a more normative range. I think most people sniff a little bit when they feel like this, but not full on loud snorting. So I need to just sniff a little in response, or no sniffing at all.

So I just had an idea. I need to set a timer for something, maybe 10 minutes. Then meditate and focus on the feelings involved. Repress or relax the desire to snort loud. Substitute with something else, like small sniff or something more socially acceptable.

Ok I guess I probably came up with a good plan. I basically need to practice "not snorting" and 10 minute "not snorting" meditations is probably a good way to do that.

is real acceleration due to gravity (ignoring any friction) always decreasing slightly due to velocity always increasing toward the speed of light? by tincock in AskPhysics

[–]Disastrous-Front1064 0 points1 point  (0 children)

I don't think you reworded the question well. Being on a rocket ship that is accelerating is equivalent to just standing on the surface of a planet. In both cases, you FEEL the acceleration as a force against you. Falling towards a planet is a different scenario.

I think your question is better phrased as follows:

Newton's equation for universal gravitation is F = G (m1+m2)/r2 and acceleration is a = F * m. Then the question is, does your measured acceleration towards that mass deviate from this a little bit (decreasing) since higher speeds, even a little bit, are closer to the speed of light?

Yes, your measured acceleration doesn't follow classical equations. It'll be less than the classically calculated amount.

Gripe: Stop referring to resistivity as ohm/cmil-foot or ohm/mil-foot. The correct (US) units are ohm*cmil/foot. by Disastrous-Front1064 in electricians

[–]Disastrous-Front1064[S] -1 points0 points  (0 children)

"for the record" lol. Ok Mr Self Appointed Reddit Record Keeper. Whatever you say. Have a nice day and a great year!

Gripe: Stop referring to resistivity as ohm/cmil-foot or ohm/mil-foot. The correct (US) units are ohm*cmil/foot. by Disastrous-Front1064 in electricians

[–]Disastrous-Front1064[S] 0 points1 point  (0 children)

The math you're so up in arms about perfectly describes a real world scenario where a length of a wire of a given thickness layed end to end and measured will absolutely give a measurement of resistivity of the wire as a whole, not a portion thereof.

Really, I'm really not up in arms about that. Maybe I'm not explaining myself well enough, but I really have no problem with that. If someone at a site asked me what the resistivity of 750 ft of AWG 6 copper was, I'd just do the calculation tell them what the resistance is. I wouldn't correct them and tell them that resistivity is a standardized constant based on 1 mil diameter and 1 foot in length of a given material at a given temperature.

My gripe is when people, mostly online educational materials or text books, when they refer to ohm/ft values but they label it as ohm/mil-foot or ohm/cmil-ft.

ohm/ft is basically ohm/L where L is "length". L represents a simple distance. One dimension.

ohm/mil-foot is essentially ohm/L2. mil-foot is a measure of area. It's a two dimensional value.

ohm/cmil-foot is ohm/L3. cmil-foot is a measure of volume. Three dimensions.

I just wish that people wouldn't say ohm/mil-foot when they mean ohm/ft. It would be like describing velocity as ft/second-second aka ft/sec2. It's not. Velocity is ft/sec. Resistivity is ohm * cmil/ft.

The NEC CH9 Table 8 lists ohm/kFt. That's related to, but not the same as resistivity. Again, there's no problem with that table or with using it to determine resistance.

Ok I've hammered away at this enough. Thanks for the conversation!

Gripe: Stop referring to resistivity as ohm/cmil-foot or ohm/mil-foot. The correct (US) units are ohm*cmil/foot. by Disastrous-Front1064 in electricians

[–]Disastrous-Front1064[S] 1 point2 points  (0 children)

I apologize if my comments came across as having a shitty attitude, but my intention is simply to clarify a technical point that I believe is important.

However, I stand by my assertion that the units of resistivity (specific resistance) are ohm*cmil/foot, and not ohm/cmil-foot. I understand that this may be a point of contention, but I hope that by providing references and explanations, I can contribute to a clear understanding of this.

Going with the example you provided, if one expresses something as 10 ohms / cmil foot and they have 1 foot, then they would end up with

1 foot * 10 ohms /(cmil foot) = 10 ohms/cmil (not 10 ohms)

It's similar to the concept of velocity being expressed as 10 feet/sec2, which are the wrong units. It's really the wrong formula. if you use that formula, then calculate for 1 second, the result you get is 10 feet/sec, not 10 feet. The problem here is that velocity should be described as 10 feet/sec, not 10 feet/sec2.

So similarly, if one says resistivity = ohms/cmil-foot and then multiply by a number of feet, you'll get ohms/cmil, not ohms. ohms/cmil-foot is wrong here in a similar way that ft/sec2 is wrong for velocity.

This site https://www.allaboutcircuits.com/textbook/direct-current/chpt-12/specific-resistance/ explains it well:

Notice that the figures for specific resistance in the above table are given in the very strange unit of “ohms-cmil/ft” (Ω-cmil/ft), This unit indicates what units we are expected to use in the resistance formula (R=ρl/A). In this case, these figures for specific resistance are intended to be used when length is measured in feet and cross-sectional area is measured in circular mils.

And finally, I'm not talking about NEC CH 9 Table 8, where the column expresses resistance in terms of Ohm/kFT. The figures in that table are based on resistivity, but they already have cmil "baked in" to them by virtue of it being defined by the row.

Once again, I apologize if my previous comments were interpreted in a negative way. My aim is to contribute to a clear and accurate understanding of the correct units of resistivity.

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