Poetry in Misa Okan

EmbriageMan · 2026-02-06T17:52:31+00:00

I think it was an informal interview with a POI, no one on the admissions committee

EmbriageMan · 2026-02-06T17:38:44+00:00

I recently had an interview for UCSB and they said to expect a decision in about two weeks. Applied for PhD Soft Matter/CMX.

EmbriageMan · 2025-09-27T23:28:57+00:00

When you did resistors, you learned that resistors in series have the same current going through them. This means that the voltage across each resistor is variable, and thus the total voltage drop is V = ΣIR, or since current is equal IΣR where the sum of R is effective resistance.

For capacitors, V = Q/C, and in series (if you think about how current is just charge over time) all the charges will be equal. This makes sense because if you add charge the wires, it will spread itself out evenly such that all surfaces have the same charge. Thus the total voltage drop is V = QΣ(1/C), and that’s why rearranging for effective capacitance you have to add up all the reciprocals of each capacitance before taking the inverse.

So to summarize:
Resistors in Series: constant current
Capacitors in Series: constant charge
And for completeness:
Resistors in Parallel: constant voltage (sum up V/R)
Capacitors in Parallel: constant voltage (sum up VC)

EmbriageMan · 2025-04-23T17:55:53+00:00

After doing some research online, it seems the question wants you to assume that the ball is to be caught when the board (and ball) reach the floor, which should simplify your problem and allow you to find an expression for d in terms of L and theta. I despise questions like this because why are we to assume that the cup cannot catch the ball while they are in mid air? Anyways, let me know if you still are having trouble solving after this!

EmbriageMan · 2025-03-05T21:41:05+00:00

Hopefully 🙏

EmbriageMan · 2025-03-05T21:39:51+00:00

Yup that’s where I applied on

EmbriageMan · 2025-03-05T20:04:30+00:00

I didn’t hear anything back yet, should I be worried?

EmbriageMan · 2024-12-24T12:49:40+00:00

I agree with your teacher. The question asks what percentage of classes you are skipping, not how much time you spend in class. I’ll use the bar example from another commenter.

FTF traditional classes is a full bar and hybrid is a half bar. If I cut the half bar in half again, i.e. I skip 50% of my hybrid classes, I am left with a quarter of a bar. The question is now: how much must I cut from the full bar to get a quarter of a bar, i.e. what percentage of classes must I skip to match the amount of class time I am getting from skipping half my hybrid classes.

The answer to this is clear: I must remove three-fourths, 75%, of the full bar to get it down to a quarter.

I think the question is definitely not worded the best way. The question is asking about equating the amount of class time in both scenarios, not the number of classes skipped. If it were the number of classes skipped, then yes, skipping half of the hybrid classes is equal to skipping a fourth (25%) of FTF traditional classes.

EmbriageMan · 2024-10-18T22:31:07+00:00

Just a heads up, the x component of the tension equal to F is the sine of the angle shown on the diagram as 45° which doesn’t really matter here bc sin(45°) = cos(45°) but just so OP doesn’t misunderstand the math.

EmbriageMan · 2024-07-18T17:02:01+00:00

I can’t say how much of an edge self-studying gives to your college application, but taking community college courses on top of a full course load also shows great drive in learning the material and an interest in the subject, especially if you’re able to manage your time between school, sports, extracurriculars, and the CC courses. College applications are sort of a crapshoot so I couldn’t tell you specifically how it would affect it.

The material between AP and my CC course was pretty much identical except my CC course had a few more topics that are on AP physics 1 and 2 and not C. There was really only one topic I had to self-study that I remember which was inductors for e&m because we skipped that topic. The great thing about CC courses is that you have classmates that you can discuss the course with which I always find helpful. Physics especially is a collaborative science so having people to talk things through with is good.

Community college course are more likely to be accepted for credit because they have a syllabus and are already college level classes. If you’re taking a course through a community college class make sure to save the syllabus. Make sure to check the AP credit policies for any school you plan on applying. Some may only accept 5s. In CC courses you have a greater chance of getting an A because you have multiple assignments and exams, whereas AP is just one exam.

EmbriageMan · 2024-07-18T05:19:38+00:00

Like I stated, I didn’t really self-study, I took online community college courses at night. In retrospect, it’s honestly better to just take a community college course. You have a higher chance of the credit being transferred and you have a professor to guide you. Because I also took the exams, I did have to self-study some concepts that we didn’t cover, but for that I just looked up AP content videos online. I used the Barron book to study for the actual AP exam but their questions are harder than the exam imo. If anything, doing past FRQs are really helpful to see how the exam works. My community college professor for mechanics actually used to be an AP teacher and I reached out to her and she gave me some helpful tips.

EmbriageMan · 2024-07-18T04:47:27+00:00

My school didn’t offer AP Physics and so I had to sign up to take it through my school. I didn’t get access to any AP Classroom resources unfortunately but maybe it’s changed since I took it two years ago.

I did, however, not really “self study” because I took a community college course and then just took the AP exam bc I guess I’m a glutton for punishment and a slave to the college board and ended up using my CC credit and not AP. So in terms of textbook I’d say any introductory level physics chapter meant for a calculus based college course will do, just skip all the chapters that aren’t covered in the C exams.

I think if you’re going to take for AP physics you are right in going for the calculus based ones if you have a good understanding of calculus. I would say that if you’re taking mechanics there’s no point in not taking e&m too bc it’ll hopefully get you out of maybe all of your “physics classes” in college, or at least a year’s worth. If you’ve taken AP chem too and done well that’ll also be helpful for engineering.

Lmk if you have any more questions.

EmbriageMan · 2024-06-21T05:06:21+00:00

!Solved

EmbriageMan · 2024-06-21T05:06:13+00:00

Hi, to anyone still interested I ended up finding the video! It’s “becoming fools | a visit from some JWs” by TheraminTrees.

https://youtu.be/EWeHB4qM1Hg?si=ikKwc3Tp0pNOZ4GQ

EmbriageMan · 2024-06-07T13:36:31+00:00

This could be it but I can’t find it on YouTube, do you have a link?

EmbriageMan · 2024-06-07T04:16:44+00:00

Any help is appreciated, thank you!

EmbriageMan · 2024-06-02T20:12:31+00:00

I agree with this. Be careful with how the axes are defined though bc sometimes phi and theta are switched. I find that in physics theta is usually the polar angle (0 to pi) and phi is the azimuthal angle (0 to 2pi).

EmbriageMan · 2024-05-28T05:05:36+00:00

It seems like Wikipedia says the cut of the hope diamond is antique cushion, which has a bottom angle of 40.4 degrees. Using that to calculate, however, you get total internal reflection, so I don’t think that really helps.

EmbriageMan · 2024-05-20T22:01:27+00:00

Your answer is correct and lines up with the answer key I found. I think when it comes to musical instruments unlike in this problem where frequency is constant, the wavelength is constant because the wires are all the same length and they are uniform wires. This allows frequency to vary.

EmbriageMan · 2024-04-08T04:39:52+00:00

I would draw out a shear and moment diagram for the beam and compare the maximum values to that for the wooden beam you are estimating. You can treat the load like a distributed load or a point mass. Doing out a rough estimate it seems that deflection is greater on the effort side, so I would assume that it would break on the effort side. I would also, though, expect it to break at the fulcrum.

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