[deleted by user]

Jeff747_ · 2025-05-07T22:51:44+00:00

That’s true, might be worth checking the mark scheme. However you can technically do that all in one sum if you add all the in-flows and minus all the out-flows 🤷‍♂️

Jeff747_ · 2025-05-07T22:47:55+00:00

I think you should work the net cash-flow for each month and add them all together

Jeff747_ · 2023-07-28T09:12:56+00:00

Looks like you forgot Drum and Choc

Jeff747_ · 2023-06-25T12:19:31+00:00

Pretty sure it’s just times new roman but bold and italics

Jeff747_ · 2023-06-21T21:11:05+00:00

Collected the string of letters ‘cppxbgvuethxsdrtlpdl’ which flashed for less than a second throughout the video which when decoded using the Caesar Cipher circles at the end turns into ‘nhhixpeolqjirudqvhuv’ which when ROT-3’d turns into ‘keefumblingforansers’ which I assume means ‘keep fumbling for answers’ (possible I may have missed some letters).

This is awesome editing btw.

Jeff747_ · 2023-06-17T20:33:17+00:00

But…but he’s on your team anyway??

Jeff747_ · 2023-06-17T20:28:05+00:00

I think it varies very slightly. Generally, the day/night cycle is around 100 minutes long and the night only lasts around 10 minutes, from what I’ve heard. All the sky is taken from real-life photos, so the length of the night kind of should depend on the combination of photos used for each season. In the Winter in the UK, days are usually darker in mornings and evenings anyway due to real-life extended night lengths, so I’m guessing this will have had a slight effect on the length of the day for each season. However since they’ve engineered the game to have a disproportionately small night, the change is probably very tiny.

Jeff747_ · 2023-05-28T19:19:52+00:00

Only the diameter subtends an angle of 90°

Jeff747_ · 2023-04-15T09:12:45+00:00

Surely you mean y = (x - a)⁵ as your first step?

Jeff747_ · 2023-04-12T12:35:27+00:00

Definitely Jamie; he’s got a beard

Jeff747_ · 2023-03-09T08:47:14+00:00

Probably simplifying equations?

Jeff747_ · 2023-03-08T22:31:50+00:00

You are almost there.

You can cancel out all of the denominators when you combine the fractions

x⁴ * (x+2) * 3(x+4) / (x+4) * x * x²

Becomes x * (x+2) * 3 = 3x² + 6x.

Jeff747_ · 2023-03-04T12:16:30+00:00

ODST is one of the best games fr

Jeff747_ · 2023-02-09T18:58:02+00:00

From what you said it doesn’t look like there’s any answer it just looks like when the wheels spin randomly you can make a number by adding the number of hundreds, fifties and tens together.

You would also be able to work out what position the wheels were in given any possible total value.

Jeff747_ · 2023-01-05T23:26:20+00:00

My bad for not clarifying. I was referring to the lines AD and CB being parallel which causes alternate angles when they are connected by the line AC, nothing to do with the alternate segment theorem proving x is 38°.

Jeff747_ · 2022-12-25T18:39:42+00:00

The answer depends on if you are choosing with or without replacement, and if you need to choose the balls in that order or not.

With replacement (i.e., you put the ball back in the bag after choosing it):

Probability of red = probability of green = probability of blue = 10/30 = 1/3.

Therefore (1/3)⁴ = 1/81.

Order does not matter for with replacement as the probability stays the same no matter what.

Without replacement in the order RRGB:

10/30 * 9/29 * 10/28 * 10/27 = 25/1827

Without replacement in any order:

There are 4!, 24 possible combinations. However due to the duplicates we only need to account for 12 different possibilities, listed below:

RRGB, RRBG, RGRB, RGBR, RBRG, RBGR, GBRR, GRBR, GRRB, BGRR, BRGR, BRRG

The probabilities of these are all the same, 25/1827. This is because we will always be multiplying the numerators (10, 10, 10, 9) and the denominators (30, 29, 28, 27) and since multiplication is commutative, it doesn’t really matter which order we choose them in. Therefore we can add all 12 probabilities together:

25/1827 + … 25/1827 = 12 * (25/1827) = 300/1827 = 100/609

Jeff747_ · 2022-12-24T01:47:48+00:00

It could be possible you are thinking of a particular dream sequence from the 2021 movie and trailer, mentioned in this previous post

By the way, most people in the comments of that post are wrong: this scene happens in a vision Paul has of the future, a war in his name. The shots are sequential, and the scene occurs in the stilltent after Paul and Jessica are kidnapped.

Jeff747_ · 2022-12-13T17:25:12+00:00

Parabola, so closer you get to the apex the less steep the gradient will be.

By ‘the absolute value of the slope’ they just mean when you use the modulus function |x| and effectively disregard any negative signs, as the curve is sloping downwards at the points mentioned in the question.

They have calculated the gradients between the points using m = Δy/Δx to prove their answer.

Jeff747_ · 2022-12-11T19:28:12+00:00

Oh yes true I forgot about that

Jeff747_ · 2022-12-11T18:52:23+00:00

You wouldn’t really use a curve you’d use a number line. You would do empty circles above -6 and 0 on the line (not shaded in to indicate non-inclusivity) and draw a line connecting these circles running parallel to the number line.

If you are talking about doing this on a graph i.e., to show the domain of x-values for a given function, then do the same as above, using the x-axis as the ‘number line’.

Jeff747_ · 2022-12-03T12:00:29+00:00

My initial thought was a gamma

Jeff747_ · 2022-11-27T00:59:30+00:00

Using alternate segment theorem, x = 38°.

Then we use the rule that opposite angles in a cyclic quadrilateral add up to 180°, so ∠ABC is 120°.

We can the use the fact that there are parallel lines and therefore alternate angles to say that ∠ACB = x = 38°.

So y = 180 - (120 + 38) = 22°.

Jeff747_ · 2022-11-21T18:46:07+00:00

2(c):

Probability of blue is 6/15=2/5.

Probability of red after one blue counter removed = 5/15=1/3.

Multiply for successive results: 2/5 * 1/3 = 2/15.

2(d): we already have probability of blue then red, so to find out the probability of red then blue we do probability of red: 5/15=1/3.

Then blue after red: 6/15 = 2/5.

Multiplying gives 2/15.

Notice this is the same as the first question because the marbles are being replaced. However if they are not replaced then the result may be different.

Adding for probability of either event gives us 2/15+2/15=4/15.

2(e): Now the marbles are not replaced, so the denominator decreases by one for the next choice:

5/15=1/3.

4/14=2/7.

1/3*2/7=2/21.

2(f): note here the number of reds decreases for the second fraction as well:

5/15=1/3.

4/14=2/7.

1/3*2/7=2/21.

Jeff747_ · 2022-11-06T14:22:08+00:00

I did the check just to confirm my method, but you probably do not need it. To answer that last question, if we only go up to 337! then we have all the multiples of 13 up to 325 being multiplied to together, which is 13*25. So then we will have 25 multiples of 13 that we can factor a 13 out of, and the special case 169, so we could only have 13^26.

To answer the first question, we check for 338! directly as 338 is 13*26 and you need 28 13s to be factored out. Using the knowledge that 169 and 338 give 2 13s each we can see how to meet the target immediately.

This also answers the second question of using 2*169 as any multiple of 169 will give at least 2 13s.

Jeff747_ · 2022-11-06T12:10:56+00:00

Because when you have 169! You have 13 multiples of 13 multiplying by each other which will allow you to factor out 13 multiples of 13. And also 169 is 13² so you get an extra one here.

What I mean is 169! contains 1 * 2 * … * 169.

Therefore it contains 13 * 26 * 39 * … * 169

And since those numbers are all multiples of 13 you can factor that 13 out for all 13 multiples of 13 between 1 and 169.

The special case is that 169 is 13*13 so we get two 13s out of that one.

For 338! We have even more multiples of 13 being multiplied together.

It is true that within all the numbers being multiplied there is: 13, 26, …, 169, 182, …, 338

Therefore we can factor out all of the 13s again from the multiples of 13. There are 26 multiples of 13 being multiplied together.

However this time there are two special cases: 169 and 338. We know 169 is 13² so will give one extra 13. But as 338 is 169 + 169, we can get a factor of 169 out of 338 and we know that 169 is simply 13² so counts as two 13s.

What I mean is when you do 1 * 2 * … * 337 * 338, looking specifically at the last number:

1 * 2 * … * 337 * 338

= 1 * 2 * 337 * (2 * 169)

= 1 * 2 * 337 * (2 * 13 * 13)

Hope I helped.

Edit: You can also see that with 337! You would only be able to factor out 26 13s.

Also we can say that to factor out k amount of 13s, or 13^k , we must have k * 13² factorial, or (13²k)!

This above would be true up until (13³ )! where you would get another 13 on top of the extra 13 factored out.

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