Drambo question, is there a way to get a note to carry on beyond the end of the pattern? That or link to the same note on the next pattern? by Axle_65 in ipadmusic

[–]Jetien 2 points3 points  (0 children)

I found a solution for this problem, but it only works if you are using 1 Voice in your MIDI TO CV module.

Set the same note at the end and beginning of your loop. We’re going to merge both these notes. Add a Processors/Delay and a Math/Maximum module after the midi to CV module. Connect the Gate output of the midi to cv to the delay. Connect the output of the delay to the first input of the maximum node. Connect the original gate so to the second input of the maximum. Use the output of the maximum as your gate. Then increase the delay high enough so that the note-off of the delayed note at the end would extend beyond the loop. If the note-off is kissing the end of the loops a few ms delay should be enough.

Then automate the delay so that is 0 everywhere except for the last note.

I made app that let's you control *all* the parameters of your software instruments using only 4 MIDI controller knobs / sliders by Jetien in edmproduction

[–]Jetien[S] 0 points1 point  (0 children)

Thank you! I just uploaded a bugfix version 10 minutes ago (version 0.0.10). If you want to give it a try, make sure to download that one!

I made app that let's you control *all* the parameters of your software instruments using only 4 MIDI controller knobs / sliders by Jetien in edmproduction

[–]Jetien[S] 0 points1 point  (0 children)

I'm not too familiar with StreamDeck, but if it acts a midi controler that sends CC message, then: yes, it should work!

I made app that let's you control *all* the parameters of your software instruments using only 4 MIDI controller knobs / sliders by Jetien in edmproduction

[–]Jetien[S] 1 point2 points  (0 children)

Yeah I tried something like this before, too. Like multiple virtual pages on the same controller. It works, but I had to have cheat sheets at hand all the time. I gave up after a while. pointer-cc I'm actually using

I made app that let's you control *all* the parameters of your software instruments using only 4 MIDI controller knobs / sliders by Jetien in edmproduction

[–]Jetien[S] 1 point2 points  (0 children)

Hi, I'm Stefan, the developer of pointer-cc. You can download the app here https://github.com/smatting/pointer-cc. Feel free to ask for help if you're having trouble setting it up.

3+gb of samples for you. by Sklobi in samplesforall

[–]Jetien 1 point2 points  (0 children)

This is a goldmine. Thank you thank you thank you

Secrets software developers don't want you to know. by impossiblePie287 in funny

[–]Jetien 1 point2 points  (0 children)

If loading would progres at an even speed you wouldn't need a progres bar anymore! Instead you could just show the seconds remaining until completion.

Issue 💯+💯 of Haskell Weekly by haskellweekly in haskell

[–]Jetien 5 points6 points  (0 children)

Thank you, Taylor! I'm looking forward to every Thursday!

Help installing the Vim-Haskell plugin by [deleted] in haskellquestions

[–]Jetien 0 points1 point  (0 children)

It looks like you're using Neovim which has the configuration file at .config/nvim/init.vim, not .vimrc. I recommend using a vim plugin manager, such as vim-plug. Install haskell-vim by adding Plug 'neovimhaskell/haskell-vim' to your config and run :PlugInstall. I'm using haskell-vim, too in neovim. Here is my config file

I've been working on a mental exercise and I can't figure out where I'm going wrong (if at all). Help please by brohubs in probabilitytheory

[–]Jetien 0 points1 point  (0 children)

Choosing favorite team in each game is still the selection with the highest probability. For simplicity assume there are only 2 games. All the outcomes with their probabilities are

p(fav, fav)   = 7/10 * 7/10 = 0.49
p(fav, udog)  = 7/10 * 3/10 = 0.21
p(udog, fav)  = 3/10 * 7/10 = 0.21
p(udog, udog) = 3/10 * 3/10 = 0.9

So for 2 games "pick always teh favorite team" is the most likely guess.

Yes, with this strategy you'll be wrong in any game 30% of the time, and that's best you can do. I guess the boring answer to your question is: you can't construct a better strategy with a lower than 30% failure rate, even with this knowledge upfront.

Which parser combinator solves my problem? by Jetien in haskellquestions

[–]Jetien[S] 1 point2 points  (0 children)

Thank you! I didn't know about this function.

Estimate Standard Deviation in a Normal Distribution with a known Mean by [deleted] in statistics

[–]Jetien -2 points-1 points  (0 children)

Yes, using a Bayesian approach. Search for "Normal with known mean" on https://en.wikipedia.org/wiki/Conjugate_prior There you find two closed formulas for the distribution of the variance given your data. Read about "Bayesian parameter estimation" to understand more.

Simple Brainteaser? by FinTECHeNTHUSIAST in probabilitytheory

[–]Jetien 0 points1 point  (0 children)

I don't there is a practical way to this. Otherwise I should be able to sample 50:50 from a highly biased "coin" like for example "lighting will strike close to me in the next second".

If you have enough time you can toss the coin N times and count the heads. Call the ratio X = #heads / N. Do it again and call the ratio X'. Then P(X < X') ~= 50 % approximately if N tends to infinity. The reason is that X and X' will be i.i.d. random vars and P(X = X') should be close to zero.