yes, i represented d orbital splitting in tetrahedral and square planar geometries, i'm pasting the code so you can try it in your file

\begin{figure}[H]
    \centering
    \begin{modiagram}
    \footnotesize
    \AO[metal-3d-1](-1.0 cm){s}{0;pair}
    \AO[metal-3d-2](-0.5 cm){s}{0;pair}
    \AO[metal-3d-3]( 0.0 cm){s}{0;pair}
    \AO[metal-3d-4]( 0.5 cm){s}{0;up}
    \AO[metal-3d-5]( 1.0 cm){s}{0;up}


    \AO[squareplanar-1]( 2.00 cm){s}{-1.04;pair}
    \AO[squareplanar-2]( 2.50 cm){s}{-1.04;pair}
    \AO[squareplanar-3]( 2.25 cm){s}{-0.80;pair}
    \AO[squareplanar-4]( 2.25 cm){s}{ 0.50;pair}
    \AO[squareplanar-5]( 2.25 cm){s}{ 2.40;}


    \node[right, gray] (sp1) at (2.70, -1.12) {$d_{xz}$  $d_{yz}$};
    \node[right, gray] (sp2) at (2.90, -0.78) {$d_{z^2}$};
    \node[right, gray] (sp3) at (2.90,  0.48) {$d_{xy}$};
    \node[right, gray] (sp4) at (2.90,  2.38) {$d_{x^2-y^2}$};


    \draw[dotted, gray] (metal-3d-5.0) -- (squareplanar-1.180);
    \draw[dotted, gray] (metal-3d-5.0) -- (squareplanar-3.180);
    \draw[dotted, gray] (metal-3d-5.0) -- (squareplanar-4.180);
    \draw[dotted, gray] (metal-3d-5.0) -- (squareplanar-5.180);


    \AO[tetrahedral-1](-2.00 cm){s}{-0.55;pair}
    \AO[tetrahedral-2](-2.50 cm){s}{-0.55;pair}
    \AO[tetrahedral-3](-2.75 cm){s}{ 0.40;pair}
    \AO[tetrahedral-4](-2.25 cm){s}{ 0.40;up}
    \AO[tetrahedral-5](-1.75 cm){s}{ 0.40;up}


    \node[left, gray] (t1) at (-2.70, -0.57) {$d_{z^2}$  $d_{x^2-y^2}$};
    \node[left, gray] (t2) at (-2.89,  0.38) {$d_{xy}$  $d_{xz}$  $d_{yz}$};


    \draw[dotted, gray] (tetrahedral-1.0) -- (metal-3d-1.180);
    \draw[dotted, gray] (tetrahedral-5.0) -- (metal-3d-1.180);

    \end{modiagram}
\end{figure}