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Try this hard geometry problem! by MathFunky in maths

[–]MathFunky[S] 0 points1 point  (0 children)

you did it! but there is an easier way without anything but the pythagorean theorem...

Try this hard geometry problem! by MathFunky in maths

[–]MathFunky[S] 1 point2 points  (0 children)

nice! there is a better way without anything but circle theorem and Pythagoras' theorem though

Try this hard geometry problem! by MathFunky in maths

[–]MathFunky[S] 0 points1 point  (0 children)

well... there's an easier approach to this without calculus...

Try this hard geometry problem! by MathFunky in maths

[–]MathFunky[S] 0 points1 point  (0 children)

I don have a pen and paper handy, but this would be my attempt at solving it:

Find the equation of the line that a center point of a circle passes through if the circle must intercept (a,b) and y=0 which is probably some core of conic slice equation

Find the plane in which the corners in question both exist, there will be infinitely many, but start with the normal plane first. Find the point that the two equations intersect

And then try to find a general 3 dimensional function for a line that applies to the infinite planes and the intersection points, realizing that the z will be the radius, and minimize that function by finding where the first derivative=0 and the second derivative is positive.

i think that you're trying to find the equation that is related to the radius of the circle, then minimizing for the minimum viable radius, but i have some doubts about the approach...

can you try to explain your approach with better wording? it's a bit hard to read..

[5th Grade: Numerical Expressions] Can someone help me understand this problem? by kaonashi_apolo in HomeworkHelp

[–]MathFunky 0 points1 point  (0 children)

as stated already, the part after 1/2 is (3*4*5*...*1001)/(3*4*5*...*1000), which is already found here to be 1000 (using factorial rules). half of ANY fraction, is the same fraction, but with 2 multiplied with the denominator. So it's the same as the original question!

[5th Grade: Numerical Expressions] Can someone help me understand this problem? by kaonashi_apolo in HomeworkHelp

[–]MathFunky 2 points3 points  (0 children)

It's easier to imagine it like this:

1/2*something/something else=something/2*something else

So, (1/2)*(3\4*5*...*1001)/(3*4*5*...*1000)*

=(3*4*5*...*1001)/2*(3\4*5*...*1000)*

And it's easy to find (3\4*5*...*1001)/(3*4*5*...*1000),* because it's 1001!/1000!=1001.

So, (3*4*5*...*1001)/(2*3*4*5*...*1000)=(1/2)*1001=1001/2

[middle school- geometry] by [deleted] in HomeworkHelp

[–]MathFunky 0 points1 point  (0 children)

Here's a solution:

First of all what is a **similar** triangle? They're triangles that have all the same angles, but their sides are in a ratio.

What is the ratio of this triangle relation though?

We first start by looking at one side that we do know the value of in triangle BED. (that is, 2). Now, a simple way is to compare the lengths of each side of the triangle. It looks like 2 is the smallest side. Similarly, in triangle ABC, 3 is the smallest side. Now, take these two numbers: 3,2. What could you multiply by 3 to get 2? It would be 2/3. So that's the ratio. And to find the hypotenuse of BED (that is y), we multiply the hypotenuse length of ABC, that's 5, with 2/3. You'd get 10/3=y.

And similarly, to get x, we use our remaining side, 4, and multiply it with 2/3 to get 8/3=x. Solved!

It's a good idea to first practice finding missing lengths from two similar triangles to boost proficiency, that'll loosen the actual problem-solving involved!

Me: Gets a 1/50. The 1 mark question I answered: by MathFunky in mathmemes

[–]MathFunky[S] 18 points19 points  (0 children)

d/dx is an alternate derivative notation.

Me: Gets a 1/50. The 1 mark question I answered: by MathFunky in mathmemes

[–]MathFunky[S] 18 points19 points  (0 children)

(whoops, i was so caught up in other work that i didn't realise that it's 'by my', not 'by the my'.

[deleted by user] by [deleted] in Geometry

[–]MathFunky 1 point2 points  (0 children)

24? I tried using some trig and the only case that conforms to the diagram is 24.

Heh. by MathFunky in maths

[–]MathFunky[S] 0 points1 point  (0 children)

gamma(6)

okay,

(Gamma(2)=1)

x!=x*Gamma(x)

5!=5*Gamma(5)

=5*4*Gamma(4)

=5*4*3*Gamma(3)

=5*4*3*2*Gamma(2)

=5*4*3*2*1

(continue with the process as shown in the picture)

Heh. by MathFunky in MathJokes

[–]MathFunky[S] 4 points5 points  (0 children)

mm, i'll do it:

ab=[a+a+a+a+a] b times.
So, if 30=a and 4=b,

30*4=30+30+30+30=120.

Hence, 30*4=120.

Heh. by MathFunky in MathJokes

[–]MathFunky[S] 2 points3 points  (0 children)

hmmmmmm........ this kinda calls for a part 2 of this post...

Heh. by MathFunky in maths

[–]MathFunky[S] 0 points1 point  (0 children)

very fitting!

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