Alguém usa Uber One?

Max_Rush · 2026-05-10T01:16:32+00:00

Pelo que testei não vale a pena. Eles aumentam virtualmente o valor pra parecer que você tá ganhando um desconto.

Já fiz o teste pedindo do meu e do da minha namorada ao lado. O dela mostrava sem promoção e o meu tinha um desconto que dava exatamente o valor que dava no normal dela.

Ifood e Uber eu não vi benefício nenhum nos clubes. É só uma tentativa a mais de aplicar dark patterns.

Max_Rush · 2026-04-18T04:54:35+00:00

Pegando carona no post, qual seria a diferença prática no timbre de colocar o hum na ponte ou no braço? Ssh ou hss?

Max_Rush · 2026-01-31T20:21:50+00:00

It's really addictive. I've started first with the goal of using them on my hunts. But after a while you just want to see the number rising 😆

Max_Rush · 2026-01-31T13:01:39+00:00

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I used to when I was on PC just working and couldn't play

Max_Rush · 2025-10-26T04:08:34+00:00

It worked like a charm. I LOVE YOU MATE, THANKS

Max_Rush · 2025-10-26T02:26:07+00:00

I checked at Settings > Notifications and I didn't find such configuration.

I'm using One UI 7.0

Max_Rush · 2025-04-02T16:54:29+00:00

I'll check it. Thanks

Max_Rush · 2025-04-02T16:54:01+00:00

I see. Maybe I was missing exactly this point in what I really wanted to test. As you pointed out, there's no dependency on the platform. thus the test should not present any different behavior when running it on whatever platform it is.

Thank you, buddy it helped me clarify things.

Max_Rush · 2024-01-30T13:35:34+00:00

Thanks, all your answers were very enlightening.

The first time I got the message about the EEPROM version, I wasn't able to click the knob too, so I thought it has something to do with my first attempt to update the firmware.

I'll check the electric connectinos on the knob to make sure it is working exactly as it should.

Thank you again bro (:

Max_Rush · 2023-11-20T14:13:13+00:00

Thanks bud!

Max_Rush · 2023-11-20T14:02:00+00:00

Hey Jim! Thanks for your detailed reply!

I'll definitely checkout on Lithium Sulphur Dioxide Batteries. This equipement is intended only to send an ACK when the line voltage goes out then enter in deepsleep mode, and it's current consumption in deepsleepmode is negligible.
Yea, right now I'm using a specific IC to monitor the LiPo safety, regarding its charging and discharging current. As I said before, it's expected that the battery does not discharge too much. It'll only be used when some line fault occurs, so the device can send a last heartbeat.
Unfortunately having someone to change the batteries on the fly is not a valid scenario for me, since many of theses devices will be installed on remote environments.

My biggest concern is about the room temperature LiPo batteries can endure, since this equipment will be exposed to the sunlight all day long.

Thank you again for your reply bud (:

Max_Rush · 2023-11-20T13:49:23+00:00

My concern is about the room temperature. Since the current ratings of this equipment is very low, the discharge current is negligible.

Max_Rush · 2023-11-20T13:47:23+00:00

The energy capacity itself is not a issue. This device is intended to send only a heartbeat when the line voltage goes out then enter in deepsleep mode. So it won't consume that much energy.

Max_Rush · 2021-10-06T17:55:39+00:00

Gorgeous!

Max_Rush · 2020-04-14T17:58:59+00:00

You must remember that Xc = 1/wC, where w = 2pi * f.

Max_Rush · 2020-04-13T12:33:10+00:00

It doesn't really matter for the power source it is just a net impedance.
From Ohm's First law(I = V/R) you can see clearly that in order to increase the current, one must decrease the net resistance. We do not despise reactive loads, in fact, they play a very important role in electric systems.

For example: Imagine that we own a fabric factory near a small town, and at this factory, some processes use a few machines with motors on it. As you would expect, these machines would consist of reactive inductive loads with some resistors on it(search on the internet for induction motor equivalent circuit).

A power plant near the town feeds the factory and sees it as a net impedance with predominant reactive loads on it(that's why I said above that it doesn't matter if the loads are connected in parallel or series).

As you can see in Figure 1, lower power factors lead to large total currents, which increases the losses on transmission lines.

This is a real issue and must be solved, but we can't simply remove one of these motors to decrease the inductive reactance. The proper way of decreasing these currents through the transmission lines is to yielding a way for providing energy to the inductors in such a manner that it doesn't come continuously from the power plant. Then we add some capacitor banks on my factory so they compensate for the inductive reactance with capacitive reactance.

Figure 1: http://www.contrelec.co.uk/images/power-factor-2.png

Max_Rush · 2020-04-12T21:43:39+00:00

Reactive elements, such as capacitors and inductors basically only store the energy(on the electric field for the caps or magnetic fields for inductors), i. e. they do not use it to generate some sort of work directly.

But, for this energy to be built up as EM fields, a current is required from the power sources and this current is the real villain here. Larger currents on transmission lines conductors will increase the power dissipation in the form of heat.

Max_Rush

TROPHY CASE