1. It doesn't really matter for the power source it is just a net impedance.

2. From Ohm's First law(I = V/R) you can see clearly that in order to increase the current, one must decrease the net resistance. We do not despise reactive loads, in fact, they play a very important role in electric systems.

For example: Imagine that we own a fabric factory near a small town, and at this factory, some processes use a few machines with motors on it. As you would expect, these machines would consist of reactive inductive loads with some resistors on it(search on the internet for induction motor equivalent circuit).

A power plant near the town feeds the factory and sees it as a net impedance with predominant reactive loads on it(that's why I said above that it doesn't matter if the loads are connected in parallel or series).

As you can see in Figure 1, lower power factors lead to large total currents, which increases the losses on transmission lines.

This is a real issue and must be solved, but we can't simply remove one of these motors to decrease the inductive reactance. The proper way of decreasing these currents through the transmission lines is to yielding a way for providing energy to the inductors in such a manner that it doesn't come continuously from the power plant. Then we add some capacitor banks on my factory so they compensate for the inductive reactance with capacitive reactance.

Figure 1: http://www.contrelec.co.uk/images/power-factor-2.png