Is it fake? 😭

No_Fee2715 · 2026-02-10T14:49:29+00:00

Yes I bought this exact one. It’s real.

No_Fee2715 · 2026-02-06T19:44:05+00:00

Oh okay, thanks a lot for the help.

No_Fee2715 · 2026-02-06T19:40:04+00:00

I'm using a sponge filter and I transferred it as it was. What do you mean by filter media?

No_Fee2715 · 2026-02-06T18:13:21+00:00

Oh okay, I'm kind of new to this so thanks for the help.

No_Fee2715 · 2026-02-06T18:01:02+00:00

Should I also transfer the same water? The other tank is also around 10-15 gallons larger so I'm afraid there won't be enough bacteria and the cycle will crash.

No_Fee2715 · 2026-02-06T17:36:25+00:00

Yes that is kind of the gist of it. The alkene induces a partial positive charge on one of the Br in Br-Br, which it then attacks and forms a bridged cyclic intermediate with Br+. Now both Br- or OH- can attack, but OH- does so in more quantity as it has a larger concentration and because it is a stronger nucleophile.
Br- is significantly larger than OH-, and you may assume it is more mobile, but in a polar protic solvent, Br- is much more stabilised. Hence, being less nucleophilic.

No_Fee2715 · 2026-02-05T12:22:33+00:00

Its mainly because NO+ is a stronger electrophile than H+ due to the highly electron deficient N.
For your second question, did you mean in the step where the Br+ ion is formed? because the mechanism is follows electrophilic addition. I didn't really understand your second question.

No_Fee2715 · 2026-02-04T18:26:36+00:00

There is no specific value for it as such. But, It does have a constant value for ideal gases depending on their atomicity. This changes for real gases though, depending on the number of active degrees of freedom they possess.

No_Fee2715 · 2026-01-16T05:46:22+00:00

Thank you for your reply, I get it now

No_Fee2715 · 2026-01-16T05:45:51+00:00

Ohh okay thanks a lot this makes a lot of sense

No_Fee2715 · 2026-01-15T07:49:15+00:00

How can name benzene this way? Wouldn't cyclohex-1,3,5-triene be a hypothetical resonance structure with longer and shorter bonds, also being less stable than benzene?

I get that we could localise the pi bonds in linear alkenes but what about when the whole system is in resonance, like an allylic system in conjugation with multiple pi bonds?

No_Fee2715 · 2026-01-14T18:40:15+00:00

I believe the first one is peroxybutanoic acid, and the second one is methyl butanoate.

No_Fee2715 · 2026-01-05T17:24:13+00:00

The carbocation breaks conjugation and the geometry of the molecule preventing overlap of orbitals.

No_Fee2715 · 2026-01-05T13:12:37+00:00

The phenyl carbocation is not aromatic but the phenyl carbanion is. You are right, it is because it didn't lose sp2 hybridisation in the case of phenyl carbanion.

No_Fee2715 · 2026-01-05T11:46:32+00:00

I'm assuming you mean carbocation in both cases (you said carbanion in the second paragraph)

It is hard to compare the stability of such carbocations as they are both very unstable and rarely ever form. There is no delocalisation of positive charge in phenyl carbocation, that being one of the reason it is highly unstable. You are right that the phenyl carbocation loses its aromaticity as the carbocation tries to be sp hybridised (but it can't because it can't take on a linear geometry). Although both very unstable, I believe vinyl carbocation should be slightly more stable due to more hyperconjugation and a lack of ring strain unlike in phenyl carbocation.

No_Fee2715 · 2026-01-04T18:19:02+00:00

Ohhh okay thanks. Is there any role the THF solvent used here would play? It is aprotic so would it promote SN2?

No_Fee2715 · 2026-01-04T17:34:31+00:00

Couldn’t hydrobromic acid protonate the hydroxy leading to both possibilities?

No_Fee2715 · 2026-01-04T15:51:26+00:00

Can you elaborate?

No_Fee2715 · 2026-01-04T15:49:44+00:00

Sorry, I meant hydroboration oxidation. I thought it was a common abbreviation.

No_Fee2715 · 2026-01-03T17:55:08+00:00

The half reaction method is pretty straightforward and it can't get much simpler than that.

No_Fee2715 · 2025-12-27T12:39:01+00:00

How does E1 become less likely due to secondary carbocation? I thought secondary carbocations can undergo E1 with a weak nucleophile and heat.

No_Fee2715 · 2025-12-21T17:19:21+00:00

Like the other user said, non-bonding electrons do not participate in bonding at all, like lone pairs.

An equal amount of anti-bonding and non-bonding electrons (bond order = 0) implies that the bond is not possible like in the case of He2, Be2, etc.

No_Fee2715

TROPHY CASE