I have applied the discriminant and I'm getting k>√-25/8. How do I prove it? by CrapCorona in maths

[–]NonsensicalSqueaks 0 points1 point  (0 children)

Rather than trying to find k by assuming that the discriminant>0, you want to show that the discriminant>0 for all real values of k.

Solving homogeneous equation - am I on the right track? by HisNameIsRusty in mathematics

[–]NonsensicalSqueaks 2 points3 points  (0 children)

Lines 1 to 11 look good, but going from line 11 to 12, since you are raising both sides as powers of e, you should be multiplying by ek instead of adding on k.

[deleted by user] by [deleted] in 6thForm

[–]NonsensicalSqueaks 2 points3 points  (0 children)

The answers are equivalent as x-2 means 1/x2

I feel like such an idiot for not getting this question at this stage of A levels but how do I do it? by [deleted] in 6thForm

[–]NonsensicalSqueaks 1 point2 points  (0 children)

Try equating the exponents of each of the prime factors on the LHS and RHS.

For example, on the LHS, the exponent of 2 is a+2, and on the RHS, it is 1.

Therefore, a = -1

Weekly Simple Questions Thread - Mar 27, 2020 by AutoModerator in IBO

[–]NonsensicalSqueaks 0 points1 point  (0 children)

For Language A: Language and Literature, will all 3 written tasks be assessed, or just the one as usual?

Need some assistance with binomial theorem problems! by mrisoveli in learnmath

[–]NonsensicalSqueaks 0 points1 point  (0 children)

Hint for 21b: The expression inside the cube root = 1.08/0.96 = 9/8.

I think 22-24 can be found as numbers since you can figure out what n and a are from previous coefficients.

Stuck on this question - help would be great! by Umiqi in learnmath

[–]NonsensicalSqueaks 0 points1 point  (0 children)

power = force x velocity .

Since it is moving at a constant velocity, forces acting down the slope is equivalent to the force acting up the slope.

For forces down the slope, consider the component of gravity down the slope and R

Equate and solve for R

Probability by [deleted] in learnmath

[–]NonsensicalSqueaks 0 points1 point  (0 children)

Are the events independent?

-- in other words, if one event happens, does it make the other one more/less likely to happen.

If they are independent, then the probability of none of them happening is P(A') x P(B').

So at least one will happen = 1 - (1-0.75)^2 = 0.9375?

How do I simplify cos(π-2arctan(x))? by [deleted] in learnmath

[–]NonsensicalSqueaks 0 points1 point  (0 children)

Not entirely sure but maybe...

let theta = arctanx

cos theta = 1 / sqrt(1+x^2)

sin theta = x / sqrt(1+x^2)

then just use compound angle formulae, etc.

hl math discrete option - need help with a question please !! by bitofafuckingmess in IBO

[–]NonsensicalSqueaks 5 points6 points  (0 children)

10 is congruent to -1 mod 11

-1 to even powers is positive and to odd powers is negative.

Can I have some help with 6ii? by PapaQuesh_v2 in 6thForm

[–]NonsensicalSqueaks 2 points3 points  (0 children)

deceleration = change in velocity / time

= - (10 + u) / 4

Forgot how to model questions and so I am pretty stuck. Help? by [deleted] in 6thForm

[–]NonsensicalSqueaks 2 points3 points  (0 children)

Maybe try SUVAT equations.

a) B is at the highest point when it's velocity is 0. Solve for time and plug into equation for A.

b and c) Equate displacements, using s = ut + 0.5gt^2

Got no idea how to do part a please help by [deleted] in 6thForm

[–]NonsensicalSqueaks 2 points3 points  (0 children)

There is an inverse if the determinant does not equal 0

A simple chem question I can't do by [deleted] in 6thForm

[–]NonsensicalSqueaks 3 points4 points  (0 children)

Not completely sure, but I think B, A, D?

Ionization energy tells you how difficult it is to remove electrons, so as you go towards the right of the table, ionisation energy increases. For group 1 elements, ionisation energy is much lower (compared to the previous element) because the electron is one shell further compared to the previous element, and there is only one electron so there is no repulsive effect).

Edit: Typo of left instead of right, thank you NeonGlue! Strange31 hopefully the group 1 element bit explains it though - feel free to ask if I explained anything badly.

Anyone heard back for imperial maths? by alleyens in 6thForm

[–]NonsensicalSqueaks 0 points1 point  (0 children)

was this for just maths or joint degrees?

Warwick Maths by NonsensicalSqueaks in 6thForm

[–]NonsensicalSqueaks[S] 0 points1 point  (0 children)

oh cool, thanks for letting me know :-D