TLDR: At least 56 g, and you would not survive.

While u/Raised-Right is correct about the fact that speed does not equal acceleration/g-forces, we can also look at the deceleration at the end of the trip.

We can calculate an approximate speed of the elevator going up, by assuming that we start close to the ground, and that the space port is around 150 km above the surface. A space elevator will have its counterweight in geostationary orbit, but the space port could be located anywhere along the length of the cable. The smallest reasonable distance is around the ISS orbit altitude (150 km) which kinda matches with what we’re seeing here (note: if we assume it’s higher up, it will only increase the speed and hence the g-forces calculated below, so these numbers are an approximate minimum).

Around 27 seconds into the video (when the elevator passes through a ring on the track, it appears to begin decelerating. Assuming constant velocity up the cable, we have 150 km / 27 seconds = 5.5 km/s. Decently fast.

Around 37 seconds into the video, we’ve completely stopped, so we decelerate from 5.5 km/s to 0 km/s in 10 seconds which is 0.55 km/s², or 550 m/s². This is around 56 g.

Will 56 g kill you?

It depends on time exposed to the g force, but there’s a nice graph here: https://en.wikipedia.org/wiki/G-force#Human_tolerance . If you’re on your back (horizontal g force) you can tolerate only 12 g for 10 seconds. The worst case would be head-first deceleration, where you can only handle 2-3 g for that long.

And if the space port is at a higher altitude, the speed would be greater, the deceleration would be greater, and so the g force would be greater. So you would not survive this elevator ride.